Average Velocity in 2D Motion
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- 5.4 m/s
- 6.2 m/s
- 7.6 m/s
- 8.8 m/s
When a person leaves his home for sigthseeing by his car, the meter reads 12352 km, When he returns home after two hours the reading is 12413 km.
(a) What is the average speed of the car during this period?
(b)What is the average velocity.
A ball of mass , moving with a velocity of , collides with a spring of length and force constant . The length of the compressed spring is . The value of , to the nearest integer, is _______
- F is v5
- D is v3
- C is v√32
- B is v
- r
- 2r
- r2
- r4
It is 260 from Patna to Ranchi by air and 320 km by road. An Aeroplane takes 30 minutes to go from Patna to Ranchi Whereas a delux bus takes 8 hours.
(a) Find the average speed of the plane.
(b) Find the average speed of the bus.
(c) Find the average velocity of the plane.
(d) Find the average velocity of the bus.
A particle is moving in a straight line. Its displacement at time is given by , then its velocity and acceleration at time second are
The acceleration of a cart started at t =0, varies with time as shown in figure (3-E2). Find the distance travelled in 30 seconds draw the position-tome graph.
The motion of a particle is defined by the equations and in , where is in . Determine the normal and tangential components of the particle’s velocity and acceleration when
- v2√1+2cos2θ
- v2√1+cos2θ
- v2√1+3cos2θ
- v cosθ
A train of 150 m in length is going towards the north direction at a speed of 10.5 m/s. A parrot flies at a speed of 4.5 m/s towards the south direction parallel to the railway track. What is the time taken by the parrot to cross the train?
- 2 K
- Zero
- 4 K
- 3 K
- ωT4
- ωT2
- ωT
- 3ωT4
The velocity of a particle at any in moving in a straight line is given by where metre is the distance travelled in seconds. What is the time taken by the particle to cover a distance of ?
A boy walks for 1 minute at a speed of 1 m/s and then runs for 1 minute at a speed of 3 m/s along a straight track. Calculate the average speed of the boy.
- 90∘
- 60∘
- 45∘
- 30∘
- 3.14 s
- 0.628 s
- 0.0628 s
- 0.314 s
A train moves at a constant speed of 60.0 km/h towards east for 30 min, then in a direction 30∘ east of due north for 20.0 min, and then west for 45 min. What are the (a) magnitude(in km/min) and (b) angle of its average velocity during this trip?
Magnitude=
Magnitude=
Magnitude=
Magnitude=
Statement II: Retardation is equal to the time rate of decrease of velocity.
- Both statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1.
- Both statement 1 and statement 2 are correct and statement 2 is not the correct explanation of statement 1.
- Statement 1 is correct and statement 2 is incorrect.
- Statement 1 is incorrect and statement 2 is correct.
Draw a velocity versus time graph of a stone thrown vertically upwards and then coming downwards after attaining the maximum height.
A stone lying at the edge of a road falls down into a river flowing below the road. If the stone takes seconds to reach the river, the find (i) the speed with which the stone strikes the water surface in the river, (ii) the average speed of the stone at the end of the fall and (iii) the height of the road from the river.
- The collision will be averted
- The collision will take place
- They will across each other
- They will just collide
A car travels along a circular track of a radius of 50 m. It takes 20 seconds to complete one rotation.
Calculate (i) speed (ii) Velocity of the car .
- √12 sec
- 4 sec
- 3 sec
- √15 sec
- 1.52
- 1.96
- 2
- 1.45
(A) Average speed of a particle can never be less than the magnitude of average velocity.
(B) We may come across ∣∣∣d→vdt∣∣∣≠0 but ddt|→v|=0.
(C) The average velocity of a particle is zero in a time interval but instantaneous velocity is never zero in that interval.
- Only A and B are correct
- Only B and C are correct
- Only A and C are correct
- A, B and C are correct
If a man is driving at an average speed of . Find the distance covered in .