Question

A particle moves with constant speed $v$ along a regular hexagon $ABCDEF$ in the same order. Then the magnitude of the average velocity for it’s motion from $A$ to

• A. $F$ is $\frac{v}{5}$
• B. $D$ is $\frac{v}{3}$
• C. $C$ is $\frac{v\sqrt{3}}{2}$
• D. $B$ is $v$

Answer 1

Answer: (A), (C), (D)

The correct options are
A $F$ is $\frac{v}{5}$
C $C$ is $\frac{v\sqrt{3}}{2}$
D $B$ is $v$

(A) $A$ to $F$
Average velocity $=\frac{\text{Total displacement}}{\text{Total time}}$
$=\frac{a}{5a/v}=\frac{v}{5}$
(B) $A$ to $D=\frac{2a}{3a/v}=\frac{2}{3}v$
(C) $A$ to $C=\frac{a\sqrt{3}}{2a/v}=\frac{v\sqrt{3}}{2}$
(D) $A$ to $B=\frac{a}{a/v}=v$