Energy Levels
Trending Questions
The shortest wavelength for the Lyman series is . Find the shortest wavelength for Paschen and Brackett series in the Hydrogen atom.
Consider the reaction . What is the quantity of electricity in coulombs needed to reduce mol of ?
None of these
The transition from the state n = 4 to n = 3 in a hydrogen-like atom results in ultra violet radiation. Infrared radiation will be obtained in the transition. (IIT-JEE-2001)
- 2→1
- 5→4
- 4→2
- 3→2
- 1218 ∘A
- 216 ∘A
- 6578 ∘A
- 1016 ∘A
- 1625λ0
- 2027λ0
- 2720λ0
- 2516λ0
- 3.4 eV
- 10.2 eV
- 12.1 eV
- 13.6 eV
The potential energy of a diatomic molecule is a function dependent on r (interatomic distance) as . Where, and are positive constants. The equilibrium distance between two atoms will . Where =_______
- 1 : 3
- 27 : 5
- 5 : 27
- 4 : 9
- 4→3
- 2→1
- 3→2
- 4→2
- 3→2
- 4→2
- 5→4
- 2→1
- 48.5 eV
- 10.2 eV
- 1.9 eV
- 13.6 eV
- λ1=λ2−λ3
- λ1=λ3−λ2
- 1λ1=1λ3−1λ2
- 1λ1=1λ2+1λ3
- 1 : 2 : 3
- 1 : 4 : 9
- 4 : 9 : 36
- 3 : 2 : 1
- 11114 ∘A
- 114 ∘A
- 14 ∘A
- 4 ∘A
- 6563 ∘A
- 1025.5 ∘A
- None of these
- 2025 ∘A
- two
- one
- three
- four
- rn∞n
- rnα1n
- rnαn2
- rnα1n2
transfer electron from first orbit to third orbit is
- 13.6 eV
- 3.4 eV
- 12.09 eV
- 1.51 eV
- 3.4 eV
- 13.6 eV
- 54.4 eV
- 122.4 eV
- n22
- (n−1)22
- n(n−1)2
- (n(n−1))22
In a hydrogen discharge tube, it is observed that through a given cross-section 3.13×1015 electrons are moving per second from right to left and 3.12×1015 protons are moving from left to right per second. The electric current in the discharge tube and its direction will be
1.6 μA towards left
1 mA towards right
1.6 μA towards right
1 mA towards left
Calculate the shortest and longest wavelengths in the hydrogen spectrum of the Lyman series.
- 1.05×10−34 Js
- 2.11×10−34 Js
- 3.16×10−34 Js
- 4.22×10−34 Js
- 27:5
- 5:27
- 4:1
- 1:4
- 2
- 5
- 3
- 4
Which element has the highest binding energy?
- 3
- 4
- 5
- 6
- Balmer series
- Lyman series
- Paschen series
- Pfund series