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Question

The wavelength of radiation emitted is λ0 when an electron jumps from the third to the second orbit of hydrogen atom. If the electron jumps from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be

A
1625λ0
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B
2027λ0
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C
2720λ0
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D
2516λ0
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Solution

The correct option is B 2027λ0
Wavelength of radiation in hydrogen atom is given by
1λ=R[1n211n22]1λ0=R[122132]=R[1419]=536R ...... (i)
and 1λ=R[122142]=R[14116]=3R16 ....... (ii)
From equation (i) and (ii) λλ=5R36×163R=2027λ=2027λ0

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