Gauss's Law
Trending Questions
A point charge of 2.0 μC is at the centre of a cubic Gaussian
surface 9.0 cm on edge. What is the net electric flux through the
surface?
Electric charge is uniformly distributed along a long straight wire of radius 1 mm. The charge per cm length of the wire is Q coulomb . Another cylindrical surface of radius 50 cm and length 1 m symmetrically encloses the wire as shown in the figure. The total electric flux passing through the cylindrical surface is
A long cylindrical volume contains a uniformly distributed charge of density ρ. Find the electric field at a point P inside the cylindrical volume at a distance x from its axis (figure 30-E5)
If the radius of the gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change?
The dimension of is the permittivity of free space, is the electric field
What is the electric flux through a cube of side which encloses an electric dipole?
Difference between plane angle and solid angle
(1ϵo=4π×9×109)
- 162π×10−3Nm2C
- 162π×103Nm2C
- 162π×10−6Nm2C
- 162π×106Nm2C
The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q1=−14 nC, q2=78.85 nC, q3=−56 nC)
- 103 Nm2 C–1
- 103 CN-1 m–2
- 6.32 X 103 Nm2 C–1
- 6.32 X 103 CN-1 m–2
Which charge configuration produces a uniform electric field?
Point charge
Infinite uniform line charge
uniformly charged infinite plane
uniformly charged spherical shell
Gauss's law should be invalid if
The velocity of light were not a universal constant
There were magnetic monopoles
The inverse square law were not exactly true
None of these
Find the flux of the electric field through a spherical surface of radius R due to a charge of 10−7 C at the centre and another equal charge at a point 2R away from the centre (figure 30-E2).the point P, the flux of the electric field through the closed surface
(a) will remain zero (b) will become positive
(c) will become negative (d) will become undefined .
- EA>EB
- EA<EB
- EA=EBr
- EA=EBr2
A charge Q is placed at the centre of an imaginary hemispherical surface. Using symmetry arguments and the Gauss's law, find the flux of the electric field due to this charge through the surface of the hemisphere (figure 30-E3).
A charged shell of radius carries a total charge . Given as the flux of electric field through a closed cylindrical surface of height , radius & with its center same as that of the shell. Here the center of the cylinder is a point on the axis of the cylinder which is equidistant from its top & bottom surfaces. Which of the following are correct.
- 2πR2E
- πR2/E
- (πR2−πR)/E
- Zero
A charge Q is uniformly distributed over a rod of length l. Consider a hypothetical cube of edge l with the centre of the cube at one end of the rod.Find the minimum possible flux of the electric field through the entire surface of the cube.
- -4 X 103 C
- 4 X 103 C
- 34
- 1
- 14
- 12
Figure 20.17 shows a spherical Gaussian surface and a charge distribution. When calculating the flux of electric field through the Gaussian surface, the electric field will be due to
+q1and+q3
+q1, +q3and−q2
+q3alone
+q1, and−q2
A parallel plate capacitor whose capacitance is is charged by a battery to a potential difference between its plates. The charging battery is now disconnected and a porcelain plate with is inserted between the plates, then the plate would oscillate back and forth between the plates, with a constant mechanical energy of . (Assume no friction)
Write some important characteristics of electric field lines.
What is null point