Question

The electric flux for Gaussian surface A that enclose the charged particles in free space is $(given{q}_1=-14nC,q_2=78.85nC,q_3=-56nC)$

• A. 10³ Nm² C^–1
• B. 10³ CN^-1 m^–2
• C. 6.32 X 10³ Nm² C^–1
• D. 6.32 X 10³ CN^-1 m^–2

Answer 1

The correct option is (A)

Step 1, Given data

Step 2, Finding the electric flux

We know,

Flux is due to charges enclosed per ${ϵ}_0$
$\therefore$ Total flux $=(-14+78.85-56)nC/{ϵ}_0$
$=8.85\times {10}^{-9}C\times \frac{4\pi }{4\pi {ϵ}_0}=8.85\times {10}^{-9}\times 9\times {10}^9\times 4\pi$
$=1000.4N{m}^2/Ci..e.1000N{m}^2{C}^{-1}$

Hence the electric flux is ${10}^{3}N{m}^2$ /C