Inductor
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Q.
In the figure, given that VBB supply can vary from 0 to 5.0 V, VCC=5 V, βdc=200, RB=100 kΩ, RC=1 kΩ and VBE=1.0 V. The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively:
In the figure, given that VBB supply can vary from 0 to 5.0 V, VCC=5 V, βdc=200, RB=100 kΩ, RC=1 kΩ and VBE=1.0 V. The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively:
- 20 μA and 3.5 V
- 20 μA and 2.8 V
- 25 μA and 3.5 V
- 25 μA and 2.8 V
Q. The transfer characteristic curve of a transistor, having input and output resistances 100 Ω and 100 kΩ respectively, is shown in the figure. The voltage gain is
- 1×104
- 5×104
- 3×104
- 4×104
Q. A 40 mH inductor is connected to a 200 V, 50 Hz ac supply. The rms value of the current in the circuit is, nearly
- 2.05 A
- 16 A
- 25.1 A
- 1.7 A
Q. A pure inductor of 26 mH is connected to an ac source of 220 V. Given frequency of the source as 50 Hz, the rms current in the circuit is
[1 Mark]
[1 Mark]
- 7 A
- 14 A
- 28 A
- 742 A
Q. Match List-I with List-II :
Choose the correct answer from the options given below :
List–I | List–II | ||
(a) | ωL>1ωC | (i) | Current is in same phase with emf. |
(b) | ωL=1ωC | (ii) | Current lags behind the applied emf. |
(c) | ωL<1ωC | (iii) | Maximum current occurs. |
(d) | Resonant frequency | (iv) | Current leads the emf. |
Choose the correct answer from the options given below :
- (a)–(ii);(b)–(i);(c)−(iv);(d)–(iii)
- (a)–(iii);(b)–(i);(c)−(iv);(d)–(ii)
- (a)–(ii);(b)–(i);(c)−(iii);(d)–(iv)
- (a)–(iv);(b)–(iii);(c)−(ii);(d)–(i)
Q. Four different circuit components are given in column I-and all the components are connected across an AC source of same angular frequency ω=200 rad/s.
The information of phase difference between the current and source voltage in such situation of column -I is given in column-II.
Match the circuit components in column-I with corresponding result in column-II.
Which of the following options is the correct match?
The information of phase difference between the current and source voltage in such situation of column -I is given in column-II.
Match the circuit components in column-I with corresponding result in column-II.
Which of the following options is the correct match?
- (A)→q, r (B)→p, t (C)→p, r (D)→q, t
- (A)→p, r (B)→p, t (C)→p, r (D)→q, t
- (A)→q, r (B)→q, t (C)→q, r (D)→q, t
- (A)→p, r (B)→q, t (C)→p, r (D)→p, t
Q. An inductor (L=200 mH) is connected to an AC source of peak emf 210 V and frequency 50 Hz. The value of peak current and instantaneous voltage of the source when the current is at its peak value is respectively :
- 3.3 A, 210 V
- 6.6 A, 0 V
- 3.3 A, 0 V
- 6.6 A, 210 V
Q. A 1 Ω voltmeter has a range of 1 V. Find the additional resistance which has to be joined in series with this voltmeter, to increase the range of the voltmeter to 100 V.
- 10 Ω
- 199 Ω
- 99 Ω
- 100 Ω
Q. A 200 V, 100 Watt bulb is to be used across an A.C source of peak voltage 400 V and an angular frequency of 103 rad/s. The inductance of a choke coil to be used in series with the bulb so that the bulb won't blow off is
Q. In the following series LCR circuit, find the peak value of source current i0, voltage across capacitor VC and voltage across inductor VL at resonance, respectively.
- 5 A, 100 V, 100 V
- 2 A, 100 V, 200 V
- 10 A, 20 V, 30 V
- 5 A, 50 V, 50 V
Q. An ideal choke takes a current of 10 A when connected to an ac supply of 125 V and 50 Hz. A pure resistor under the same conditions takes a current of 12.5 A. If the two are connected to an AC supply of 100 V and 40 Hz, then the current in a series combination of the above resistor and inductor is
- 5√2 A
- 12.5 A
- 20 A
- 10 A
Q. The figure represents the voltage applied across a pure inductor. The diagram which correctly represents the variation of current i with time t is given by
Q. Given below are two statements.
Assertion - Resonance frequency will decrease in a series LCR circuit if a dielectric slab is inserted in between the plates of the capacitor.
Reason - By doing so, capacity of capacitor will increase.
Based on the above statements, choose the correct alternative.
Assertion - Resonance frequency will decrease in a series LCR circuit if a dielectric slab is inserted in between the plates of the capacitor.
Reason - By doing so, capacity of capacitor will increase.
Based on the above statements, choose the correct alternative.
- Both assertion and reason are true, and reason is a correct explanation of assertion.
- Both assertion and reason are true, but reason is not a correct explanation of assertion.
- Assertion is true, but reason is false.
- Assertion is false, but reason is true.
Q. A coil has negligible resistance and an inductive reactance of 20 Ω at 50 Hz. If an AC source of 200 V and 100 Hz frequency is connected across the coil, the rms current in the coil will be
- 2.0 A
- 5.0 A
- 7.0 A
- 10.0 A
Q. If the reading of voltmeter V shown in the figure at resonance is 200 V, then the quality factor of the circuit is,
- 2
- 4
- 1
- 3
Q. An AC circuit has R=100 Ω, C=2 μF and L=80 mH connected in series. The quality factor of the circuit is :
- 2
- 0.5
- 20
- 400
Q. A 100W/200V bulb and an inductor are connected in series to a 220V/50Hz supply. Find the power consumed by the bulb.
- 100W
- 92W
- 74W
- 84W
Q. An arc lamp requires a direct current of 10 A at 80 V to function. If it is connected to a 220 V(rms), 50 Hz supply, the series inductor needed for it to work, is close to-
- 80 H
- 0.08 H
- 0.044 H
- 0.065 H
Q. An RLC series circuit has L=10 mH, R=3 Ω and C=1 μF connected in series to a source of E=15cosωt V. If the frequency of the voltage is 10% less than the resonant frequency, then
- Peak value of current is 0.704 A
- Impedance of the circuit is 21.32 Ω
- Power factor of the circuit is 0.141
- Resonant frequency of the circuit is 9×103 rad/s
Q. As the frequency of an AC circuit increases, the current first increases and then decreases. What combination of circuit elements is most likely to comprise the circuit?
- Inductor and capacitor
- Resistor and inductor
- Resistor, inductor and capacitor
- (a) and (c) above
Q. An inductor L=20 mH, a resistor R=100 Ω and a battery E=10 V are connected in series. After a long time the battery is short-circuited. Find the current in the circuit, 1 ms after short-circuiting.
[Use e−5=0.00673]
[Use e−5=0.00673]
- 6.7×10−4A
- 2.5×10−4A
- 0.5×10−4A
- 2×10−3A
Q. An electric bulb, a capacitor, battery and a switch are all in series in a circuit. How does the intensity of light vary when the switch is turned on?
- Continues to increase gradually
- Gradually increases for some time and then becomes steady.
- Sharply rises initially and then gradually decreases
- Gradually increases for some then time and then gradually decreases
Q. A series LCR circuit containing a resistor of resistance 120 Ω has resonant frequency 4×105 rad/s. At resonance, the voltage across resistor and inductor are 60 V and 40 V respectively. Find the value of C.
- 12 μF
- 2 μF
- 19 μF
- 132 μF
Q. The angular frequency of alternating current in a LCR circuit is 100 rad/s. The components connected are shown in the figure. Find the value of inductance of the coil and capacity of condenser.
- 0.8 H and 250 μF
- 0.8 H and 150 μF
- 1.33 H and 250 μF
- 1.33 H and 150 μF
Q. A series LCR circuit is designed to resonate at an angular frequency ω0=105 rad/s. The circuit draws 16 W power from 120 V source at resonance. The value of resistance R in the circuit is Ω
Q. The inductive reactance of a coil is 1000Ω. If its self inductance and frequency both are increased two times then inductive reactance will be
- 1000 Ω
- 2000 Ω
- 4000 Ω
- 16000 Ω
Q. An inductive circuit contains resistance of 1 Ω and an inductance of 2.0 H. If an AC voltage of 120 V and frequency 60 Hz is applied to this circuit, the current would be nearly
- 0.8 A
- 0.48 A
- 0.16 A
- 0.32 A
Q.
An amplitude modulated voltage is expressed as
e=10(1+0.8cos2000πt)cos3×106πtvolt. The depth of modulation is :- 8
- 0.8
- 800
- None of these
Q. An LCR circuit contains resistance of 110 Ω and a supply of 220 V at 300 rad/s angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45∘. If on the other hand, only inductor is removed the current leads by 45∘ with the applied voltage. The rms current flowing in the circuit will be:
- 2.5 A
- 2 A
- 1 A
- 1.5 A
Q. A charged capacitor discharges through a resistance R with time constant τ. The two are now placed in series across an AC source of angular frequency ω=1τ . The impedance of the circuit will be:
- R√2
- √2 R
- R
- 2R