Intuition of Wave Speed
Trending Questions
- 250
- 180
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- 200
Which of the following has the highest energy?
X-rays
Ultraviolet radiation
Gamma rays
Infrared radiation.
(x→in cm, y→ cm, t→in second).
What would be the speed of the wave?
- 200 cm s−1
- 100 cm s−1
- 150 cm s−1
- 50 cm s−1
- 3.6 x 10-11
- 3.6 x 10-6
- 3.6 x 10-4
- 3.6
- 7π Hz
- 10π Hz
- 3π Hz
- 5π Hz
Two blocks each having a mass of 3.2 kg are connected by awire CD and the system is suspended from the ceiling by another wire AB (figure 15-E5). The linear mass density of the wire AB is 10 g m−1 and that of CD is 8 g m−1. Find the speed of a transverse wave pulse produced in AB and in CD.
- 300 m/s
- 30 m/s
- 400 m/s
- 40 m/s
Two parts of a sonometer wire divided by a movable bridge differ in length by and produce when sounded together. The total length of the wire is , then the frequencies are
and
and
and
and
Reason: The wave corresponding to given equation is travelling towards positive x−direction.
- Both assertion and reason are correct and reason is the correct explanation of assertion.
- Both assertion and reason are correct but reason is not a correct explanation of assertion.
- Assertion is correct but reason is incorrect.
- Assertion is incorrect but reason is correct.
A sonometer wire having a length of 1.50 m between the bridges vibrates in its second harmonic in resonance with a tuning fork of frequency 256 Hz. What is the speed of the transverse wave on the wire ?
A stretched string is forced to transmit transverse waves by means of an oscillator coupled to one end. The string has a diameter of 4mm. The amplitude of the oscillation is 10−4m and the frequency is 10 Hz. Tension in the string is 100 N and mass density of wire is 4.2×103 kg/m3 . Find Average energy flow per unit time
5.5×10−5 J/s
6.5×10−5 J/s
7.5×10−5 J/s
4.5×10−5 J/s
If S2P−S1P=λ6, find intensity at point P.
- 4Io
- 3Io
- 2Io
- Io
y=Asin(5t−0.05x) in which A , x are in metres and t is in seconds. The value of A is
- 1:1/√(1+1/n)
- n2:1
- √n:1
- n:1
- 4m/s in + x direction
- 4m/s in - x direction
- 2m/s in + x direction
- 2m/s in - x direction
- y=asin(wt+kx)
- y=−acos(kx−wt)
- y=acos(kx−wt)
- y=−asin(kx+wt)
- 25ms−1
- 50ms−1
- 75ms−1
- 100ms−1
The equation of a travelling wave is y = 60 cos (1800t – 6x) where y is in microns, t in seconds and x in metres. The ratio of maximum particle velocity to velocity of wave propagation is
A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3 seconds. If the field strength is increased to 4 times of the earlier field strength, the time period will be :
- 6 s
- 1.5 s
- 0.75 s
- 12 s
- v=5m/s
- A=0.04m
- λ=18m
- f=50Hz
- 80 m/s, 20 √10 m/s, 40 m/s
- 20 √10 m/s, 40 m/s, 80 m/s
- 20 √10 m/s in all
- 80 m/s in all
- L1T1/2e−1/2
- L1T−1/2e−1/2
- L−1T1/2e−1/2
- L1/2T1e−1/2
Statement-2 : If a travelling wave sent along a particular string by oscillating its one end, it is the wavelength of the wave that decreases.
- If both the statements are true and statement-2 is the correct explanation of statement-1
- If both the statements are true but statement-2 is not the correct explanation of statement-1
- If statement-1 is true and statement-2 is false
- If statement-1 is false and statement-2 is true
- 12
- 1√2
- 2
- √2
- 1.17×10−2N
- 1.17×10−1N
- 1.17×10−3N
- None.
- 12
- 1√2
- 2
- √2