Law of Conservation of Mechanical Energy
Trending Questions
- v ∝ x12
- v ∝ x
- v ∝ x−12
- v ∝ x−1
- 120 m/s
- 160 m/s
- 100 m/s
- 80 m/s
- 2 m/s
- 4√2 m/s
- 2√2 m/s
- √2 m/s
What are the three equations of motion?
Which of the following property of a proton can change while it moves freely in a magnetic field? (There may be more than one correct answer.) A) mass B) speed C) velocity D) momentum
mass
speed
velocity
momentum
Two identical springs of spring constant are attached to a block of mass and to fixed support (see figure). When the mass is displaced from equilibrium position on either side, it executes simple harmonic motion. Then, time period of oscillations of this system is:
(Take g=9.8 m/s2)
- 1.4 m/s
- 0.7 m/s
- 2.8 m/s
- 3.6 m/s
Obtain an expression for acceleration of the particle performing circular motion.
- 0.7 m
- 0.2 m
- 0.5 m
- 0.6 m
- 2Mg/k
- 4Mg/k
- Mg/2k
- Mg/k
[r is the radius of circular orbit]
- Independent of r
- ∝1r
- ∝1r2
- ∝r2
A cubical vessel of height is full of water. What is the work done in pumping water out of the vessel?
- Ts=T1+T2
- T2s=T21+T22
- T−2p=T−21+T−22
- Tp=T1+T2
- cos−1(23)
- cos−1(14)
- 60∘
- 30∘
Water falls from a height o 500m what is the rise in temp of water at bottom of whole energy remains in the water
A small block of mass 100 g is pressed against a horizontal spring fixed at one end to compress the spring through 5.0 cm (figure 8-E11). The spring constant is 100 N/m. When released, the block moves horizontally till it leaves the spring. Where will it hit the ground 2 m below the spring ?
- lala−lw
- lalw
- l2la−lw
- lwla
- h=2R
- h=4R
- h=R
- h=52R
- vB<vC<vD
- vB>vC<vD
- vB=vC=vD
- vB>vC>vD
- 10 m/s
- 5 m/s
- 8 m/s
- 15 m/s
- Maximum extension of the spring is 4mgk
- Acceleration of block B is g3 downwards, when extension in the spring is mgk
- Maximum extension in the spring is 2mgk
- Acceleration of block B is g3 downwards, when extension in spring is 4mgk
The work done by the external force on a system equals the change in _________ energy.
- 2 cm
- 5 cm
- 10 cm
- 20 cm
- √5mg2k
- √8mg2k
- √6mg2k
- √7mg2k
- Mgl2
- √3Mgl2
- Mgl√2
- 2Mgl√3
A body of mass is thrown vertically up with a kinetic energy of . The height at which the kinetic energy of the body becomes half of the original value is
- 2mgk
- 3mgk
- 3mg2k
- mg2k
Two masses of 4 kg and 5 kg are connected by a string passing through a frictionless pulley and are kept on a frictionless table as shown in the figure. The acceleration of 5 kg mass is
49 m/s2
5.44 m/s2
19.5 m/s2
2.72 m/s2
How do you find acceleration and velocity without time?