Newtons Second Law
Trending Questions
- 9.8 m/s
- 15 m/s
- 22 m/s
- 37 m/s
Find the average force needed to accelerate a car weighing 500 kg from rest to 72 km/h in a distance of 25 m.
- 17, 600
- 16, 000
- 14, 500
- 28, 400
A body of mass 0.40 kg moving initially with a constant speed of 10 ms−1 to the north is subject to a constant force of 8.0 N directed towards the south for 30 s. Take the instant the force is applied to be t = 0, the position of the body at that time to be x = 0, and predict its position at t = -5 s, 25 s, 100 s.
1. What was the initial acceleration of the bus?
2. What was the velocity of the bus after 5 seconds?
3. Calculate ab .
4. How long did does the bus brake?
b) Two athletes Usha and Shiney are playing athletic games. Usha is running at a constant velocity towards Shiney who is stationary. When Usha is 12 meters away from Shiney, Shiney starts to accelerate at a constant rate of 1.5ms−2.
1. What is the minimum velocity with which Usha needs to run in order to just catch up with Shiney?
2. How long does Usha take to catch up with Shiney?
- 32KW
- 8KW
- 24KW
- 16KW
(Take g=10m/s2)
- 30m
- 40m
- 72m
- 20m
A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of in . Find its acceleration. Find the force acting on it if its mass is 7 metric tonnes (Hint: 1 metric tonne .)
A 250 g block slides on a rough horizontal table. Find the work done by the frictional force in bringing the block to rest if it is initially moving at a speed of 40 cm/s. If the friction coefficient between the table and the block is 0.1, how for does the block move before coming to rest?
- 9.8 m/s
- 15 m/s
- 22 m/s
- 37 m/s
- 9.8 m/s
- 15 m/s
- 22 m/s
- 37 m/s
- d(u−v)uvlogeuv
- dvulogeuv
- dlogevuv−u
- duvlogeuv
Take the car system to be otherwise isolated (i.e. the decelerating force was the only force acting on the car).
- −1700W
- −15300W
- −30600W
- −61200W
- Cannot be determined from the information given