# Resistors in Series and Parallel

## Trending Questions

**Q.**The current (i1) (in A) flowing through 1 Ω resistor in the following circuit is

- 0.40 A
- 0.20 A
- 0.25 A
- 0.5 A

**Q.**The figure shows a circuit having eight resistances of 1 Ω each, labelled R1 to R8, and two ideal batteries with voltages ε1=12 V and ε2=6 V.

Which of the following statement(s) is(are) correct?

- The magnitude of current flowing through R1 is 7.2 A.
- The magnitude of current flowing through R4 is 2.4 A
- The magnitude of current flowing through R3 is 4.8 A.
- The magnitude of current flowing through R2 is 1.2 A.

**Q.**21.n a circuit a metallic wire is connected in series with a battery and an ammeter.if another wire(same metal, same length and cross sectional area )is connected in parallel to the metallic wire , the current in ammeter will be: A)halved B) doubled C)four times D) same

**Q.**119.An ac voltage is applied to a resistance R and an inductor L in series. If R and inductive reactance are both equal to 3 ohm, the phase difference between the applied voltage and the current in the circuit is 1) pie/6 2) pie/4 3) pie/2 4) 0

**Q.**Two resistors, 4 Ω and 6 Ω are connected in parallel with a 6 V battery of negligible resistance. Calculate the current flowing through 4 Ω resistor.

- 1 A
- 1.5 A
- 2 A
- 2.5 A

**Q.**Twelve resistors each of resistance r are connected together so that each lies along the edge of the cube as shown in the figure. The equivalent resistance between points 1 and 4 is

- 5r12
- 7r12
- 11r12
- 13r12

**Q.**The depletion layer in a silicon diode is 1 μm wide and the knee potential is 0.6 V, then the electric field in the depletion layer will be

- Zero
- 0.6 Vm−1
- 6×104 Vm−1
- 6×105 Vm−1

**Q.**In the circuit shown in figure, emf of the batteries are E1=3 V, E2=2 V, E3=1 V and their internal resistances are R=r1=r2=r3=1 Ω. The potential difference between the points A and B, and the current through branch containing resistor r2 will be respectively

- 2 V, 1 A
- 3 V, 2 A
- 2 V, 0 A
- 4 V, 1.5 A

**Q.**In the figure shown, what is the current (in Ampere) drawn from the battery? You are given:

R1=15 Ω, R2=10 Ω, R3=20 Ω, R4=5 Ω, R5=25 Ω, R6=30 Ω, E=15 V

- 20/3
- 7/18
- 13/24
- 9/32

**Q.**Consider the circuit shown in the figure

- The current in the 5 Ω resistor is 2 A
- The current in the 5 Ω resistor is 1 A
- The potential difference VA−VB is 10 V
- The potential difference VA−VB is 5 V

**Q.**Potential drop across 5 Ω is 10 V, then EMF of the battery is

- 12 V
- 28 V
- 30 V
- 40 V

**Q.**A resistor with resistance of 10 MΩ is connected in series with a capacitor of capacitance 1 μF and a battery with e.m.f. E=12 V. Before the switch is closed at time t=0, the capacitor is uncharged. What fraction of the final charge is on the plates at time, t=46 s? (e−4.6=0.01)

- 99%

- 10%
- 20%

- 50%

**Q.**In the circuit shown in figure, E1 and E2 are two ideal sources of unknown emfs. Current flowing through resistor of resistance R Ω is 2 A and through resistor of resistance 4 Ω is 3 A as shown. If potential difference across 6 Ω resistance is VA−VB=10 V, then the value of (E2−E1)R( in V.Ω) is

**Q.**In the figure shown, the potential difference between points A and B is :

- 10 V
- 30 V
- 7.5 V
- None

**Q.**Several capacitors are connected as shown in the given figure. If the charge on the 5μ F capacitor is 120μ C , the potential between points A and D is

- 24 V
- 96 V
- 16 V
- 0 V

**Q.**A 100 W and 500 W bulb are joined in parallel with the mains . Which bulb will glow brighter?Give reasons

**Q.**AB is a part of another large circuit. Also VQ−VB=12 V Then

- Current, i=3 A
- Current i=5 A
- VA−VB=12 V
- VA−VB=24 V

**Q.**In the circuit shown below, the current that flows from a to b when the switch S is closed is

- + 1.0 A
- + 1.5 A
- - 1.0 A
- - 1.5 A

**Q.**Eight identical resistances r are connected as shown in figure. Find equivalent resistance between A and D.

- 7r16
- 2r9
- 8r15
- 7r19

**Q.**

Find the charges on the four capacitors of capacitances 1μF, 2μF, 3μF and μF shown in figure (32 - E32). Figure 32 - E32

Figure 32 - E32

**Q.**

Find the current measured by the ammeter in the circuit shown in figure (32-E18)

**Q.**Two capacitors of capacitances C1 and C2 , in a circuit are joined as shown in the figure. The potential of point A is V1 and potential of point B is V2. The potential at point D will be

- 12(V1+V2)

- (C2V1+C1V2)C1+C2

- (C1V1+C2V2)C1+C2

- 2(C1V1+C2V2)C1+C2

**Q.**Three resistors having resistances, r1, r2 and r3 are connected as shown in the given circuit. The ratio i3i1 of currents in terms of resistances used in the circuit is -

- r2r1+r3
- r1r2+r3
- r2r2+r3
- r1r1+r2

**Q.**A potentiometer consists of a wire of length 200 cm and of resistance 5 ohm. It is connected to a cell of emf 1 V having negligible internal resistance. The potential difference per unit length of the wire, is (1) 1 V/m (2) 0.5 V/m (3) 2 V/m (4) 3 V/m

**Q.**In the circuit shown in the figure, a 12 volt battery has been connected across the points X and Y. The work done by battery will be:

180 μJ

384 μJ

424 μJ

212 μJ

**Q.**(a) Three resistors 1 W, 2 W, and 3 W are combined in series. Whatis the total resistance of the combination? (b) If the combination is connected to a battery of emf 12 V andnegligible internal resistance, obtain the potential drop acrosseach resistor.

**Q.**A current of 2 ampere flows in a system of conductors as shown in the following figure. The potential difference (VA−VB) will be (in volts):

- +2
- −1
- +1
- −2

**Q.**Consider an infinite mesh as shown in figure. Each side of the mesh has resistance R. Consider the hexagonal part ABCDEF of the infinite mesh. Equivalent resistance between any two points of the hexagon is measured. Equivalent resistance between A and B is αRβ. Find the least value of α+β.

**Q.**In the following figure, the potential difference is shown on R, L & C. The emf of source in volt is

- 190
- 70
- 50
- 40

**Q.**Potential drop across 5 Ω is 10 V, then EMF of the battery is

- 12 V
- 28 V
- 30 V
- 40 V