Stopping Potential vs Intensity
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Q. An electron falls from rest through a vertical dis†an ce h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical dis†an ce h . The time of fall of the electron, in comparison to time of fall of the proton i
Q. A uniform electric field E Exists between two metal plates one negative and other positively charged . The plate length is l and the seperation of the plates is d . An electron and a proton start moving parallel to the plates towards the other e from the mid point of the seperation of plates at one end of the plates . Which of the two will have greater deviation when they come out of the plates if they start with 1) same initial velocity 2)same initial kinetic energy 3)same initial momentum
Q. The surface of a metal is illuminated with the light ofWavelength 400 nm. The kinetic energy of theejected photoelectrons was found to be 1.68 eV.Work function of the metal is about(1) 3.09 eV(3) 4.73 ev(2) 1.42 eV(4) 0.68 ev
Q. When light of a given wavelength is incident on a metallic surface, the minimum potential needed to stop the emitted photoelectrons is 6.0 V. This potential drops to 0.6 V if another source with wavelength four times that of the first one and intensity half of the first one is used. What are the wavelength of the first source and the work function of the metal, respectively?
[Take hce=1.24×10−6 JmC−1.]
[Take hce=1.24×10−6 JmC−1.]
- 3.78×10–7 m, 1.20 eV
- 3.78×10–7 m, 5.60 eV
- 1.72×10–7 m, 1.20 eV
- 1.72×10–7 m, 5.60 eV
Q. 13.A current passes through a resistor. Lets K1 and K2 represent the average kinetic energy of the conduction electrons and the metal ions respectively. How to compare k1 and K2
Q.
When the light source is kept 20 cm away from a photo cell, stopping potential 0.6 V is obtained. When source is kept 40 cm away, the stopping potential will be
2.4 V
0.3 V
0.6 V
1.2 V
Q. A beam of cathode rays after gaining kinetic energy once it passes throught a potential difference of V is subjected to crossed electric (E) and magnetic fields (B). The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by
- B22VE2
- 2VB2E2
- 2VE2B2
- E22VB2