Time Period Independent of Amplitude
Trending Questions
- stays in rest
- executes simple harmonic motion
- executes oscillation but not SHM
- moves to the centre of ring immediately and stays there
- √3π232 cm/s2
- −π232 cm/s2
- π232 cm/s2
- −√3π232 cm/s2
- 2πβα
- β2α2
- αβ
- β2α
- 2π
- 3π
- π
- π2
- 21%
- 10%
- 30%
- 50%
- 14 s
- 12 s
- 13 s
- 15 s
- 25 s
- 16 s
- 13 s
- 12 s
The path followed by α particle is represented by:
- B
- A
- D
- C
R=6.3×106 m),
[Height of a polar satellite above earth's surface will be around 700 km]
- 24 hr
- 1000 min
- 100 min
- 6 hr
- t=T6
- t=T8
- t=T4
- t=T12
- T12
- T6
- 5T12
- 7T12
- 0.1256 sec
- 0.1456 sec
- 0.1556 sec
- 0.1356 sec
A large horizontal surface moves up and down in SHM with an amplitude of 1 cm. If a mass of 10 kg (which is placed on the surface) is to remain continually in contact with it, the maximum frequency of S.H.M. will be
0.5 Hz
5 Hz
1.5 Hz
10 Hz
2. If instead of the cosine function, we choose the sine function to describe the SHM : x=B sin(ωt+α), what are the amplitude and initial phase of the particle with the above initial conditions.
- Block executes simple harmonic motion.
- The block's motion is periodic but not simple harmonic.
- The frequency of oscillation is independent of the size of the block.
- The motion of the block is symmetric about its equilibrium position.
- T=2π√mR3KQq
- T=2π√mR2KQq
- T=2π√mR32KQq
- None of the above
- T4
- T8
- T2
- T6
A simple pendulum is made of a body which is a hollow sphere containing mercury suspended by means of a wire. If a little mercury is drained off, the period of pendulum will
]
Remains unchanged
Increase
Decrease
Become erratic
- The tension in the ring will be same throughout.
- The tension in the ring will be independent of its radius.
- The elongation in the ring is MgRaY
- The elastic potential energy stored in the ring will be M2g2R8πYa
- 4
- 1.57
- 0.25
- 1
A rod of length L and mass M is acted on by two unequal forces F1 and F2(<F1) as shown in the figure. The tension in the rod at a distance y from the end A is given by:
F1[1−yL]+F2[yL]
(F1−F2)yL
F2[1−yL]+F1[yL]
None of these
- 2π ⎷x22−x21v21−v22
- 2π ⎷v21+v22x21+x22
- 2π ⎷v21−v22x21−x22
- 2π ⎷x21+x22v21+v22
The function of time representing a simple harmonic motion with a period of is
- -
- -
- T=2π√lg
- T=2π ⎷l(g+Eqm)
- T=2π ⎷l(g−Eqm)
- T=2π√lmg+Eq
- 2π√σaρg
- 2π√ρaσg
- 2π√ρgσa
- 2π√σgρa
[Assume collision to be elastic with the wall and horizontal surface to be smooth]
- (π+4)√mK
- 2π√mK
- None of these
- (1+π)√mk
An open organ pipe has a length of 5 cm. (a) Find the fundamental frequency of vibration of this pipe. (b) What is the highest harmonic of such a tube that is in the audible range ? Speed of sound in air is 340ms−1 and the audible range is 20-20, 000 Hz.
A balloon going upwards with a velocity of 12m/s is at ht.65 m from earth at any instant.At this instant a packet drops from it.how much time will packet take in reaching earth?