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Question

The time period of polar satellites is about (take g=9.8 ms2 and radius of the Earth
R=6.3×106 m),

[Height of a polar satellite above earth's surface will be around 700 km]

A
24 hr
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B
1000 min
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C
100 min
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D
6 hr
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Solution

The correct option is B 1000 min
Time period of a satellite orbiting around the earth is given by,
T=2π(R+h)3gR2Where,
g=acceleration due to gravity =9.8 ms2
R=Radius of the Earth=6.3×106 m,

Height of the polar satellite above earth surface lies in between 500 to 900 km, so the average value,
h=700 km

Substituting the values in the above equation,

T=2π (6.3×106+700×103)39.8×(6.3×106)2
T=5894.29 sec

T=5894.2960=98.3100 min

Thus, time period of polar satellites is about 100 minutes

Hence, option (b) is the correct answer.

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