Question

# The time period of polar satellites is about (take g=9.8 ms−2 and radius of the Earth R=6.3×106 m), [Height of a polar satellite above earth's surface will be around 700 km]

A
24 hr
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B
1000 min
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C
100 min
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D
6 hr
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Solution

## The correct option is B 1000 minTime period of a satellite orbiting around the earth is given by, T=2π√(R+h)3gR2Where, g=acceleration due to gravity =9.8 ms−2 R=Radius of the Earth=6.3×106 m, Height of the polar satellite above earth surface lies in between 500 to 900 km, so the average value, h=700 km Substituting the values in the above equation, T=2π ⎷(6.3×106+700×103)39.8×(6.3×106)2 ⇒T=5894.29 sec ∴T=5894.2960=98.3≈100 min Thus, time period of polar satellites is about 100 minutes Hence, option (b) is the correct answer.

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