Vectors
Trending Questions
Q. Two vectors A and B have equal magnitude. If the magnitude of (A+B) is ′n′ times the magnitude of (A−B), then angle between vectors A and B is
- sin−1(n2−1n2+1)
- sin−1(n−1n+1)
- cos−1(n2−1n2+1)
- cos−1(n−1n+1)
Q. Three particles P, Q and R are moving along the vectors →A=^i+^j, →B=^j+^k and →C=−^i+^j respectively. They strike on a point and start to move in different directions. Now particle P is moving normal to the plane which contains vector →A and →B . Similarly, particle Q is moving normal to the plane which contains vector →A and →C . The angle between the direction of motion of P and Q is cos−1(1√x). Then the value of x is
Q.
A particle of mass 2 kg moves on a circular path with constant speed 10mm/s find change in speed and magnitude of change in velocity when particle completes half revolution
Q. Let the angle between two non-zero vectors →A and →B be 1200 and resultant be →C, then
- ∣∣∣→C∣∣∣ must be equal to ∣∣∣→A−→B∣∣∣
- ∣∣∣→C∣∣∣ must be less than ∣∣∣→A−→B∣∣∣
- ∣∣∣→C∣∣∣ must be greater than ∣∣∣→A−→B∣∣∣
- ∣∣∣→C∣∣∣ may be equal to ∣∣∣→A−→B∣∣∣
Q. Two vectors →X and →Y have equal magnitude. The magnitude of (→X−→Y) is n times the magnitude of (→X+→Y). The angle between →X and →Y is:
- cos−1(n2+1n2−1)
- cos−1(n2+1−n2−1)
- cos−1(n2−1−n2−1)
- cos−1(−n2−1n2−1)
Q.
An aeroplane is moving in a circular path with a speed 250 km/h what is change in velocity in half revolution
Q.
A body is moving with a uniform velocity of 10 m/s on a circular path of diameter 2.0m. calculate
1) the difference between the magnitude of the displacement of the body and the distance covered in half a round and
2) the magnitude of the changes in velocity of the body in half a round.
Q. The magnitudes of four pairs of displacement vectors are given. Which pair of displacement vectors cannot be added to give a resultant vector of magnitude 4 cm?
- 1 cm, 1 cm
- 1 cm, 3 cm
- 1 cm, 5 cm
- 1 cm, 7 cm
Q. Let →a=^i+^j+^k, →b=^i−^j+^k and →c=^i−^j−^k be three vectors. A vector →v in the plane of →a and →b, whose projection on →c is 1√3, is given by
- ^i−3^j+3^k
- −3^i−3^j−^k
- 3^i−^j+3^k
- ^i+3^j−3^k
Q. A point traversed half a circle of radius R=160cm during time interval t=10sec. Calculate the following quantities averaged over that time (a) the mean velocity (b) the modulus of mean velocity vector || (c) the modulus of the mean vector of the total acceleration ||
Q. If the sum of two unit vectors is a unit vector, then magnitude of difference is
- √2
- √3
- 1/√2
- √5
Q. The magniude of vectors \(\overrightarrow {OA}, \overrightarrow {OB}\) and \(\overrightarrow {OC}\) In the given figure are equal.\(\overrightarrow {OA}+\overrightarrow {OB}-\overrightarrow {OC}\) with x-axis will be
Q. The sum of the magnitudes of two forces is 18 N and the magnitude of their resultant is 12 N. If the resultant makes an angle of 90∘ with the smaller force, then find the magnitude of the forces.
- 5 N, 13 N
- 6 N, 12 N
- None of these
- 10 N, 8 N
Q. The sum of the magnitudes of two forces is 18 N and the magnitude of their resultant is 12 N. If the resultant makes an angle of 90∘ with the smaller force, then find the magnitude of the forces.
- 5 N, 13 N
- 6 N, 12 N
- 10 N, 8 N
- None of these
Q. Magnitude of resultant of 3 vectors −−→OA, −−→OB, and −−→OC as shown below is
- r
- 2r
- r(1+√2)
- r(√2−1)
Q. Part of commentary by a commentator of a race is given. What can you infer about it? "The racing car takes a circular turn at a constant velocity of 84 km per hour. "
- Commentary is right, car can turn at constant velocity.
- Commentary is wrong, velocity does not remain constant while turning.
- Such high speed is not possible.
- None of the above.
Q. Magnitude of resultant of 3 vectors −−→OA, −−→OB, and −−→OC as shown below is
- r
- 2r
- r(1+√2)
- r(√2−1)
Q. A radioactive element X converts into another stable element Y. Half-life of X is 2h. Initially, only X is present. After time t, the ratio of atoms of X and Y is found to be 1:4. Then t in hours is
- 2
- 4
- between 4 and 6
- 6
Q. A radioactive element X converts into another stable element Y. Half life of X is 2 hrs. Initially only X is present. After time t, the ratio of atoms of X and Y is found to be 1:4, then t in hours:
- 4
- 2
- 6
- Between 4 and 6
Q. If the sum of two unit vectors is a unit vector, then magnitude of their difference is
- √2
- √3
- 1√2
- √5
Q. Two forces each of 10N act at an angle 600 with each other. The magnitude and direction of the resultant with respect to one of the vectors is:
- √10N, 300
- 10√3N, 300
- 10√2N, 1200
- 20N, 1200
Q. The resultant of two vectors A and B subtends an angle of 45∘ with either of them. The magnitude of the resultant is
- zero
- √2A
- A
- 2A
Q. Let →a=^i+^j+^k, →b=^i−^j+^k and →c=^i−^j−^k be three vectors. A vector →v in the plane of →a and →b, whose projection on →c is 1√3, is given by
- ^i−3^j+3^k
- −3^i−3^j−^k
- 3^i−^j+3^k
- ^i+3^j−3^k
Q. The sum of the magnitude of two forces at a point is 16 N. If their resultant is normal to the smaller force and has a magnitude of 8 N. Then two forces are
- 6 N, 10 N
- 8 N, 8 N
- 4 N, 12 N
- 2 N, 14 N
Q. If SA and SB represents the displacement of block and plank w.r.t. ground respectively when block seperates, then
- SA=4V√l3g−23l
- SA=4V√lg−23l
- SB=4V√l3g−53l
- SB=4V√lg−13l
Q. Part of commentary by a commentator of a race is given. What can you infer about it? "The racing car takes a circular turn at a constant velocity of 84 km per hour. "
- Commentary is right, car can turn at constant velocity.
- Commentary is wrong, velocity does not remain constant while turning.
- Such high speed is not possible.
- None of the above.