Oxidation of Alkenes
Trending Questions
Q. Alkene R−C−H=CH2 reacts readily with B2H6 and the product on oxidation with alkaline hydrogen peroxides produces
- R−CH2−CHO
- R−CH2−CH2−OH
Q. A hydrocarbon X adds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. X reacts with KMnO4 in presence of acid to give two moles of the same carboxylic acid. The structure of X is
- CH2=CH−CH2CH2CH3
- CH3CH2CH2−CH=CHCH3
- CH3CH2CH=CHCH2CH3
- CH3CH=CHCH2CH2CH3
Q.
1, 2-Dicyanocyclohexane
Cyclohexane-1, 2-dinitrile
Cyclohexane-1, 2-dicarbonitrile
None of the above
Q. The reagent which is used to distinguish between propene and propyne is
- Bromine
- Alkaline KMnO4
- Ammoniacal AgNO3
- Ozone
Q. Cyclopentene on treatment with alkaline KMnO4 gives
- Cyclopentanol
- trans 1, 2-cyclopentanediol
- cis 1, 2-cyclopentanediol
- 1 : 1 mixture of cis and trans 1, 2-cyclopentanediol
Q. Baeyer's reagent is used in the laboratory for
- Detection of double bonds
- Detection of glucose
- Reduction
- Oxidation
Q. A hydrocarbon X adds on one mole of hydrogen to give another hydrocarbon and decolourised bromine water. X reacts with KMnO4 in presence of acid to give two moles of the same carboxylic acid. The structure of X is
- CH2=CH−CH2CH2CH3
- CH3CH2CH2−CH=CHCH3
- CH3CH2CH=CHCH2CH3
- CH3CH=CHCH2CH2CH3
Q.
On vigorous oxidation by alkaline permanganate solution (CH3)2C=CH2CHO gives:
On vigorous oxidation by alkaline permanganate solution (CH3)2C=CH2CHO gives:
- a) (CH3)2−OH|C−OH|CH−CH2CH3
b) CH3╲╱ CH3CO + CH2COOH| COOH
c) CH3╲╱ CH3CHOH+CH3CH2CH2OH
d) CH3╲╱ CH3CO+CH3CH2CHO
Q. Which of the following options is/are correct with respect to the following reaction sequence?
- Both B and C have the same degree of unsaturation
- C has 3 double bond equivalent
- C is
- C is 1-cyclopentenylethanone
Q. Which one of the following on ozonolysis followed by oxidation will give adipic acid?
- a
- b
- c
- d