Rate Constant
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By rate = K[CH3OCH3]32
The rate of reaction is followed by increase in pressure in a closed vessel and the rate can be expressed in terms of the partial pressure of dimethyl ether i.e, Rate = K(pCH3OCH3)32
If pressure is measured in bar and time in minutes, the units of rate constant are
- (bar)32min−1
- (bar)−32min−1
- (bar)−12min−1
- (bar)−1min−1
obeys first order kinetics. The initial pressure is 90 mm and after 10 minutes it is 180 mm. The velocity constant ‘k’ of the reaction is:
- 1.15×103 s−1
- 1.15×10−3 s−1
- 2.30×103 s−1
- 3.45×10−3 s−1
Time (in seconds)06001200KMnO4 sol. used (in mL)22.813.88.20
- k=8.44×10−4sec−1
- k=8.44×10−2sec−1
- k=2.44×10−6sec−1
- k=2.22×10−4sec−1
- None of these
- L mol−1s−1
- mol L−1a−1
- s−1
The following data pertains to reaction between A and B :
S.NO.[A]mol L−1mol L−1Rate(mol L−1time−1)11.0×10−22.0×10−22.0×10422.0×10−22.0×10−24.0×10−432.0×10−24.0×10−28.0×10−4
Which of the following inference(s) can be drawn from the above data ?
1. Rate constant of the reaction is 1.0×10−4
2. Rate law of the reaction is: rate =k[A][B]
3. Rate of reaction increases four times on doubting the concentration of both the reactants.
Select the correct answer using the codes given below:
1, 2 and 3
1 and 2
2 and 3
3 only
A reaction in which all reactants are in the same phase is called
elementary
bimolecular
homogeneous
heterogeneous
For the reaction : aA+bB→ Products, the rate law is given by Rate = k[A]m[B]n. On making the concentration of A two-fold and halving that of B, the ratio of the new rate to the earlier rate of the reaction would be:
n−1
m+n
2−(m+n)
2(m−n)
On the top of a certain mountain where atmospheric pressure is 535 mm Hg, pure water shows a boiling point of 360 K and it takes 3×102 min to boil at the top of the mountain as against 3 min taken to boil an egg at 370 K. The ratio of rate constants K370K360 is ?
10
1
100
110
- t = 0.693/k
- t = 6.909/k
- t = 4.606/k
- t = 2.303/k
(Given Ksp for BaSO4=1.4×10−10 )
- 1.7×10−7 M
- 2.7×10−7 M
- 7.0×10−8 M
- 7.0×10−10 M
S2−+S→S2−2equilibrium constant K1
S2−2+S→S2−3 equilibrium constant K2
K1 and K2 have the values 12 and 11, respectively.
S2−3→S2−+2S. What is equilibrium constant for the reaction?
- 132
- 7.58×10−3
- 1.09
- 0.198
The rate of the reaction for [A]=0.15 mol dm−3, [B]=0.25 mol dm−3 and [C]=0.15 mol dm−3 is found to be Y×10−5 mol dm−3s−1.The value of Y is
- 3.465×10−2min−1, 2.166×10−4mol.litre−1min−1
- 3.465×10−3min−1, 2.17×10−3mol.litre−1min−1
- 2.166×10−3min−1, 2.667×10−4mol.litre−1min−1
- 2.17×10−2min−1, 3.47×10−4mol.litre−1min−1
A reaction : A2+B→ Products, involves the following mechanism :
A2⇌ 2A (fast) (A being the intermediate)
A+B→k2(slow).The rate law consistent to this mechanism is :
rate=k[A2][B]
rate=k[A2]2[B]
rate=k[A2]12[B]
rate=k[A2][B]2
- 7.5×10−5
- 3×10−4
- 2.5×10−5
- 1.25×10−6
(i)N2O5(g)→2NO2(g)+12O2(g);−d[N2O5]dt=k[N2O5](ii)2N2O5(g)→4NO2(g)+O2(g);−d[N2O5]dt=k′[N2O5]
Which of the following is true?
- k=2k′
- k=k′2
- k=k′12
- k=k′
The chemical reaction 2O3→3O2 involves two elementary steps :
O3fast−−→O2+O;O+O3Slow−−−→2O2
The differential rate law expression will be :
rate=k[O3]2
rate=k[O3]2[O2]
rate=k[O3]2[O2]−1
rate=k[O3]2[O2]−3
By rate = K[CH3OCH3]32
The rate of reaction is followed by increase in pressure in a closed vessel and the rate can be expressed in terms of the partial pressure of dimethyl ether i.e, Rate = K(pCH3OCH3)32
If pressure is measured in bar and time in minutes, the units of rate constant are
- (bar)32min−1
- (bar)−32min−1
- (bar)−1min−1
- (bar)−12min−1
(i)N2O5(g)→2NO2(g)+12O2(g);−d[N2O5]dt=k[N2O5](ii)2N2O5(g)→4NO2(g)+O2(g);−d[N2O5]dt=k′[N2O5]
Which of the following is true?
- k=k′
- k=2k′
- k=k′2
- k=k′12
- 10−2s−1
- 10−4s−1
- 6×10−2s−1
- 6×102s−1
- mol L−1a−1
- L mol−1s−1
- s−1
- None of these
- 4.60×10−3s−1
- 6.9×10−2s−1
- 1.15×10−3s−1
- 4.90×10−3s−1
- 7.33
- 0.733
- 73.3
- 733
The following data pertains to reaction between A and B :
S.NO.[A]mol L−1mol L−1Rate(mol L−1time−1)11.0×10−22.0×10−22.0×10422.0×10−22.0×10−24.0×10−432.0×10−24.0×10−28.0×10−4
Which of the following inference(s) can be drawn from the above data ?
1. Rate constant of the reaction is 1.0×10−4
2. Rate law of the reaction is: rate =k[A][B]
3. Rate of reaction increases four times on doubting the concentration of both the reactants.
Select the correct answer using the codes given below:
1, 2 and 3
1 and 2
2 and 3
3 only
- mol−2 L2 s−1
- s−1
- mol L−1 s−1
- L mol−1 s−1
(a is the initial concentration and k is the rate constant)
- ak
- 2ka
- ak
M→N
the rate of disappearence of M increases by a factor of 8 after doubling the concentration of M. The order of the reaction with respect to M is
- True
- False