For the reaction : $a A + b B \to$ Products, the rate law is given by Rate = $k [A]^{m} [B]^{n}$ . On making the concentration of A two-fold and halving that of B, the ratio of the new rate to the earlier rate of the reaction would be:

$n - 1$

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$m + n$

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$2^{- (m + n)}$

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$2^{(m - n)}$

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Solution

The correct option is D
$2^{(m - n)}$

$(R a t e)_{1} = k [A]^{w} [B]^{n}; (R a t e)_{2} = k (2 [A])^{w} (\frac{[B]}{2})^{n}$

$H e n c e, \frac{(r a t e)_{2}}{(r a t e)_{1}} = 2^{m} \times (\frac{1}{2})^{n} = 2^{m - n}$

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For the reaction : $a A + b B \to$ Products, the rate law is given by Rate = $k [A]^{m} [B]^{n}$ . On making the concentration of A two-fold and halving that of B, the ratio of the new rate to the earlier rate of the reaction would be:

Q. The rate law for a reaction between substances A and B is given by

R a t e = k [A]^{n} [B]^{m}

On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of reaction will be:

Q. The rate law for a reaction between the substances

A

and

B

is given by,

R a t e = K [A]^{n} [B]^{m}

. On doubling the concentration of

A

and halving the concentration of

B

, the ratio of the new rate to the earlier rate of the reaction will be as:

Q. The rate law for a reaction between the substances A and B is given by
rate =

k [A]^{n} [B]^{m}

On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

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For the reaction : aA+bB→ Products, the rate law is given by Rate = k[A]m[B]n. On making the concentration of A two-fold and halving that of B, the ratio of the new rate to the earlier rate of the reaction would be:

The correct option is D 2(m−n) (Rate)1=k[A]w[B]n;(Rate)2=k(2[A])w([B]2)n Hence,(rate)2(rate)1=2m×(12)n=2m−n

For the reaction : $a A + b B \to$ Products, the rate law is given by Rate = $k [A]^{m} [B]^{n}$ . On making the concentration of A two-fold and halving that of B, the ratio of the new rate to the earlier rate of the reaction would be:

The correct option is D
$2^{(m - n)}$

$(R a t e)_{1} = k [A]^{w} [B]^{n}; (R a t e)_{2} = k (2 [A])^{w} (\frac{[B]}{2})^{n}$

$H e n c e, \frac{(r a t e)_{2}}{(r a t e)_{1}} = 2^{m} \times (\frac{1}{2})^{n} = 2^{m - n}$