Salt of Weak Acid and Weak Base
Trending Questions
Q. Find the pH of an equimolar solution of HCN and NH4OH.
Given: Ka(HCN)=6×10−10 Kb(NH4OH)=1.8×10−5
Given: Ka(HCN)=6×10−10 Kb(NH4OH)=1.8×10−5
- 8.45
- 4.74
- 12.5
- 9.24
Q. What will be the pH of an aqueous solution of 0.1 M ammonium formate 25oC?
Given : pKa(HCOOH)=3.8 and pKb(NH4OH)=4.8
Given : pKa(HCOOH)=3.8 and pKb(NH4OH)=4.8
- 6
- 6.5
- 4.5
- 5.5
Q. Consider a weak monobasic acid HA having a concentration C with degree of dissociation, α<<1.. The pH of this weak acid in terms of acid dissociation constant Ka and concentration C is :
- −log10(√KaC)
- −log10√Ka.C
- pH=−log10√Ka.C2
- pH=−log10√K2a.C
Q.
An aqueous solution of ammonium acetate is
Faintly acidic
Faintly basic
Fairly acidic
Almost neutral
Q. Find the pH of an equimolar solution of HCN and NH4OH.
Given: Ka(HCN)=6×10−10 Kb(NH4OH)=1.8×10−5
Given: Ka(HCN)=6×10−10 Kb(NH4OH)=1.8×10−5
- 8.45
- 4.74
- 12.5
- 9.24
Q. Given the Ka for acetic acid is 1.77×10−5 and Kb for ammonium hydroxide is 1.82×10−5.
Calculate the pH of an aqueous solution of ammonium acetate (CH3COONH4) at 25∘C.
Calculate the pH of an aqueous solution of ammonium acetate (CH3COONH4) at 25∘C.
- 8.115
- 8.05
- 7.01
- 7.65
Q.
An aqueous solution of ammonium acetate is
Faintly acidic
Faintly basic
Fairly acidic
Almost neutral
Q.
The degree of hydrolysis of ammonium acetate is related to its hydrolysis constant by the expression
a = Kh(1+Kh)
a = Kh(1+Kh2)
a = √Kh(1+√Kh)
a = √Kh(1+Kh)
Q. pKa of a weak acid (HA) and pKb of a weak base (BOH) are 3.2 and 3.4, respectively. The pH of their salt (AB) solution is:
- 1
- 6.9
- 7
- 7.2
Q. Which of the following mixtures can act as a buffer if equal amount of both species is mixed?
- HCN+NaCN
- HCOOH+NaOH
- NH4OH+(NH4)2SO4
- (a) and (c) above.
Q. pKa of a weak acid (HA) and pKb of a weak base (BOH) are 3.2 and 3.4. respectively. The pH of their salt (AB) solution is
- 6.9
- 1
- 7.2
- 7
Q. Which of the following statement is correct regarding an eqiumolar solution of a weak acid CH3COOH and a weak base NH4OH at 25∘C ?
- Higher the concentration of CH3COOH, lesser is the pH value.
- Higher the concentration of NH4OH, higher is the pH value.
- pH does not depend on the concentration of CH3COONH4.
- None of the above
Q. The dissociation constants for aniline, acetic acid and water at 25∘ C are 4×10−10, 2×10−5 and 10−14 respectively. Calculate degree of hydrolysis of aniline acetate in a decinormal solution.
- 0.53
- 0.15
- 0.35
- 0.45
Q. What will be the pH of an aqueous solution of 0.1 M ammonium formate 25oC?
Given : pKa(HCOOH)=3.8 and pKb(NH4OH)=4.8
Given : pKa(HCOOH)=3.8 and pKb(NH4OH)=4.8
- 6
- 6.5
- 4.5
- 5.5
Q. Which of the following describes the correct relation for pOH for an aqueous salt solution of weak acid and weak base at 25∘C ?
- pOH=14−12(pKa−pKb)
- pOH=7+12(pKa−pKb)
- pOH=7−12(pKa−pKb)
- pOH=14+12(pKa−pKb)
Q. Which of the following describes the correct relation for hydrolysis constant (Kh) for a salt of weak acid and weak base at 25∘C ?
- Kh=KwKa×Kb
- Kh=KaKw×Kb
- Kh=Ka×KbKw
- Kb=KhKa×Kw
Q. pOH=7–0.5pKa+0.5pKb is true for an aqueous solution that has which pair of cations and anions amongst the following?
- C6H5NH+3, CH3COO−
- NH+4, F−
- Na+, CH3COO−
- NH+4, Cl−