Third Law of Thermodynamics

Q.

What Is The Third Law Of Thermodynamics?

Q.

Why does water freezing not violate the second law of thermodynamics?

Q.

How do we measure entropy?

Q.

Calculate the entropy change accompanying the following change of state

$5mol$ of $O_2({27}^{\circ }C,1atm)\to 5mol$ of $O_2({117}^{\circ }C,5atm)$

$C_P$ for $O_2=6.95calde{g}^{-1}mo{l}^{-1}$

1. $-8.88calde{g}^{-1}$
2. $-6.88calde{g}^{-1}$
3. $-9.77calde{g}^{-1}$
4. $-10.77calde{g}^{-1}$

Q.

Calculate the entropy change accompanying the following change of state.

$H_{2}O(s,-{10}^{\circ }C,1atm)\to H_{2}O(l,{10}^{\circ }C,1atm)$
$C_P$ for ice = $9calde{g}^{-1}mo{l}^{-1}$

$C_P$ for $H_{2}O$ = $18calde{g}^{-1}mo{l}^{-1}$

Latent heat of fusion of ice = $1440calmo{l}^{-1}$ at $0^{\circ }C$

1. $-8.88calde{g}^{-1}mo{l}^{-1}$

2. $-7.77calde{g}^{-1}mo{l}^{-1}$

3. $-6.3calde{g}^{-1}mo{l}^{-1}$

4. None of these

Q.

Calculate the entropy change accompanying the following change of state

$5mol$ of $O_2({27}^{\circ }C,1atm)\to 5mol$ of $O_2({117}^{\circ }C,5atm)$

$C_P$ for $O_2=6.95calde{g}^{-1}mo{l}^{-1}$

1. $-8.88calde{g}^{-1}$
2. $-6.88calde{g}^{-1}$
3. $-9.77calde{g}^{-1}$
4. $-10.77calde{g}^{-1}$

Q.

For a solid at $TK{S}_T-S_0=\Delta S={\int }_O^T\frac{CpdT}{T}=C_{P}lnT=2.303C_{P}logT$

1. True

2. False