Parametric Equation of Parabola
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Q.
Calculate the ratio in which the line joining and is divided by a point . Also find
(i) .
(ii) length of .
Q. If Q be a point on the parabola y2=8x and P(−2, 0) be a point in the xy plane. If the locus of the mid point of PQ is a parabola, then its focus is
- (1, 1)
- (0, 0)
- (−1, 0)
- (0, 1)
Q. Coordinates of parametric point on the parabola, whose focus is (−32, −3) and the directrix is 2x+5=0 is given by
- (2t2+2, 2t−3)
- (12t2−2, t−3)
- (12t2−2, t+3)
- (12t2+2, t+3)
Q.
(I) Write down the coordinates of the point P, that divides the line joining and in the ratio .
(II) Calculate the distance OP, where O is origin.
(III) Find the equation of a line AB.
Q. If the ends of a focal chord of the parabola y2=4ax are (x1, y1) and (x2, y2) then x1, x2+y1y2=
- a2
- −3a2
- 5a2
- −5a2
Q. Let P be the point on the parabola, y2=8x, which is at a minimum distance from the centre C of the circle, x2+(y+6)2=1. Then, the equation of the circle, passing through C and having its centre at P is
- x2+y2−4x+8y+12=0
- x2+y2−x+4y−12=0
- x2+y2−x4+2y−24=0
- x2+y2−4x+9y+18=0
Q. The curve described parametrically by y=2at and x=at2 represents
- an ellipse
- a parabola
- a hyperbola
- a circle
Q. If θ be the angle subtended at the focus by the chord which is normal at the point (λ, λ), λ≠0 to the parabola y2=4x, then the equation of the line making angle θ with positive x−axis and passing through (1, 2) is
- y=2
- x+2y=5
- x+y=3
- x=1
Q. If the tangent at P on y2=4ax meets the tangent at the vertex in Q, and S is the focus of the parabola, then ∠SQP=
- π3
- π4
- π2
- 2π3
Q. A focal chord of the parabola y2=4ax meets it at P and Q. If S is the focus then 1SP+1SQ=
- a
- 1a
- 2a
- 2a
Q. The Cartesian equation of the curve whose parametric equations are x=t2+2t+3 and y = t + 1 is
- y=(x−1)2+2(y−1)+3
- x=(y−1)2+2(y−1)+5
- x=y2+2
- none of these
Q. The locus of a point on the variable parabola y2=4ax, whose distance from focus is always equal to k, is equal to
- 4x2+y2−4kx=0
- x2+y2−4kx=0
- 2x2+4y2−8kx=0
- 4x2−y2+4kx=0
Q. The parametric equation of a parabola is x=t2+1, y=2t+1 Then which of the following options are correct ?
- Vertex is (1, 1)
- Vertex is (−1, −1)
- Length of latus rectum of parabola is 8 units
- Length of latus rectum of parabola is 4 units
Q.
The points of intersection of the curves whose parametric equations are x=t2+1, y=2t and x=2s, y=2s Is given by
(1, - 3)
(2, 2)
(-2, 4)
(1, 2)
Q. List I has four entries and List II has five entries. Each entry of List I is to be matched with one or more than one entries of List II.
List IList II (A)Tangents are drawn from the point (2, 3)(P)(9, −6)to the parabola y2=4x. Then point(s) ofcontact is (are)(B)From a point P on the circle x2+y2=5, (Q)(1, 2)the equation of chord of contact to theparabola y2=4x is y=2(x−2). Thenthe coordinates of P are(C)P(4, −4), Q are points on parabola(R)(−2, 1)y2=4x such that area of △POQ is 6sq. units where O is the vertex. Thencoordinates of Q may be(D)The common chord of circle x2+y2=5(S)(4, 4)and parabola 6y=5x2+7x will passthrough point(s)(T)(−2, 2)
Which of the following is the only CORRECT combination?
List IList II (A)Tangents are drawn from the point (2, 3)(P)(9, −6)to the parabola y2=4x. Then point(s) ofcontact is (are)(B)From a point P on the circle x2+y2=5, (Q)(1, 2)the equation of chord of contact to theparabola y2=4x is y=2(x−2). Thenthe coordinates of P are(C)P(4, −4), Q are points on parabola(R)(−2, 1)y2=4x such that area of △POQ is 6sq. units where O is the vertex. Thencoordinates of Q may be(D)The common chord of circle x2+y2=5(S)(4, 4)and parabola 6y=5x2+7x will passthrough point(s)(T)(−2, 2)
Which of the following is the only CORRECT combination?
- (C)→(Q), (S)
- (C)→(P), (T)
- (D)→(P), (S)
- (D)→(Q), (R)
Q. The parametric equation of the curve y2=8x are
- x=t2, y=2t
- x=2t2, y=4t
- x=2t, y=4t2
- None of these
Q. If the tangent at P on y2=4ax meets the tangent at the vertex in Q, and S is the focus of the parabola, then ∠SQP=
- π3
- π4
- π2
- 2π3
Q. The parametric point (3+t2, 3t−2) represents a parabola with
- focus at (−3, −2)
- vertex at (3, −2)
- directrix x=−5
- all of these
Q.
Which of the following can be the parametric equation of
(x − 1)2 = −36(y − 4)
x = 1 + 18t and y = 4 − 9t2
x = −1 + 18t and y = −4 − 9t2
x = −1 − 18t and y = 4 − 9t2
x = 1 + 18t and y = −4 − 9t2
Q. The length of the chord of the parabola x2=4y passing through the vertex and having slope cot α is
- 4 cos α.cos ec2α
- 4 tan α sec α
- 4 sin α.sec2 α
- none of these
Q. Find the parametric equation of the parabola x2−4x−32=−12y
- x=3+6t, y=2−3t2
- x=2−6t, y=3+3t2
- x=6t, y=3t2
- x=2+6t, y=3−3t2
Q. The curve described parametrically by
x=t2+t+1, y=t2−t+1 represents
x=t2+t+1, y=t2−t+1 represents
- a pair of straight lines
- an ellipse
- a parabola
- a hyperbola
Q. An equilatral triangle inscribed in parabola y2=4ax whose one vertex is at the vertex of parabola. Then the length of the side of the triangle is
- 8√3a
- 4√3a
- 8√2a
- 4√2a
Q. The parametric equation of parabola (y−2)2=12(x−4) is
- x=4−3t2, y=2−6t
- x=2+3t, y=4+t2
- x=4+3t2, y=2+6t
- x=2+3t2, y=4+6t
Q. Vertex of the parabola whose parametric equation is x=t2−t+1, y=t2+t+1;t∈R, is
- (1, 1)
- (2, 2)
- (12, 12)
- (3, 3)
Q. Two distinct chords of the parabola y2=4ax passing through P(a, 2a) are bisected by the line x−y+1=0. The possible length of the latus rectum of the parabola when a>0 is
- 2
- 3
- 4
- 5
Q. The triangle PQR of area A is inscribed in the parabola y2=4ax such that P lies at the vertex of the parabola and base QR is a focal chord. The numerical difference of the ordinates of the points Q & R is
- A2a
- Aa
- 2Aa
- 4Aa
Q. The locus of a point which divides the line segment joining the point (0, −1) and a point on the parabola, x2=4y, internally in the ratio 1:2, is:
- 9x2−12y=8
- 4x2−3y=2
- x2−3y=2
- 9x2−3y=2
Q. If θ be the angle subtended at the focus by the chord which is normal at the point (λ, λ), λ≠0 to the parabola y2=4x, then the equation of the line making angle θ with positive x−axis and passing through (1, 2) is
- y=2
- x+2y=5
- x+y=3
- x=1
Q. The parametric equation of a parabola is x=t2+1, y=2t+1 Then which of the following options are correct ?
- Vertex is (1, 1)
- Vertex is (−1, −1)
- Length of latus rectum of parabola is 8 units
- Length of latus rectum of parabola is 4 units