Average velocity
Trending Questions
- v1+v22
- √v1v2
- √2v1v2
- 2v1v2v1+v2
- 0
- 2.5 ms
- 5 ms
- 2 ms
The magnitude of average velocity is always equal to the average speed.
- True
- False
- 5 m/s
- 4 m/s
- 4.5 m/s
- 3.5 m/s
- 4×10−3cms, 1.8×10−4cms
- 4.4×10−3cms, 1.8×10−4cms
- 0.44×10−3cms, 1.8×10−4cms
- 4.4×10−3cms, 0.18×10−4cms
When the magnitude of average velocity is the same as that of average speed?
A body is moving in a straight path. Then,
its instantaneous speed is equal to its instantaneous velocity.
its average speed is equal to its average velocity.
its acceleration is equal to a change in its velocity.
Both (a) and (b).
- 10 m/s
- 60 m/s
- 5 m/s
- 0
- v13+2v23
- v13+v23
- 2v13+v23
- v1+2v23
- 32 m/s
- 29.5 m/s
- 32.5 m/s
- 28 m/s
- 80/3 ms−1
- 40 ms−1
- 25 ms−1
- 30 ms−1
Will the average speed be greater than average velocity?
Yes
No
Under what condition(s) is the magnitude of the average velocity of an object equal to its average speed?
- 1 ms−1
- 2 ms−1
- 3 ms−1
- 4 ms−1
- −10 m/s
- 12 m/s
- 10 m/s
- −8 m/s
- 0 ms−1
- 6 ms−1
- −1 ms−1
- −2 ms−1
- 20 and zero
- 0 and 20
- 20 and 20
- 6.3 and 20
- 20 and zero
- 0 and 20
- 20 and 20
- 6.3 and 20
A body traveling along a straight line traversed one third of the total distance with a velocity 4 m/s. The remaining part of the distance was covered with a velocity 2 m/s for half of the time and with velocity 4 m/s for the other half of time. The mean velocity averaged over the whole time of motion is
5
4
0
2
- 70 km/hr
- 60 km/hr
- 110 km/hr
- 40 km/hr
The position of an elevator varies with time according to the function x(t)=t2+2t+3
Find the
(1) average velocity between time interval t=0 s to t=2 s.
(2) instantaneous velocity of the elevator at time t=3 s.
- vavg=8 m/s ; vins=11 m/s
- vavg=4 m/s ; vins=8 m/s
- vavg=8 m/s ; vins=4 m/s
- vavg=11 m/s ; vins=4 m/s
- 5 m/s
- −3 m/s
- 3 m/s
- −6 m/s
- 20√2 m
- 10√2 m
- 5 m
- 15 m
- 10 m/.s
- 16 m/.s
- 14 m/.s
- 5 m/.s
- 1314 m/s
- 1415 m/s
- 1112 m/s
- 79 m/s
The position of an elevator varies with time according to the function x(t)=t2+2t+3
Find the
(1) average velocity between time interval t=0 s to t=2 s.
(2) instantaneous velocity of the elevator at time t=3 s.
- vavg=8 m/s ; vins=11 m/s
- vavg=4 m/s ; vins=8 m/s
- vavg=8 m/s ; vins=4 m/s
- vavg=11 m/s ; vins=4 m/s
- average velocity is 253 m/s
- average velocity is 10 m/s
- average velocity is 53 m/s
- average velocity is 135 m/s
- −10 m/s
- 12 m/s
- 10 m/s
- −8 m/s
- ¯v=v1+v22
- 2¯v=1v1+1v2
- ¯v=√v1v2
- ¯v=√v2v1
- u+12at
- u+at
- u+at2
- u2