Horizontal and Vertical Components of Projectile Motion
Trending Questions
Approximately how many kilometers are represented by of latitude.
If and are any real numbers, then
none of these
- 20√3 m/s
- 20√3 m/s
- 10√3 m/s
- 10√3 m/s
इस खण्ड में 1 कथन-कारण प्रकार का प्रश्न है, जिसमें 4 विकल्प (a), (b), (c) तथा (d) दिये गये हैं, जिनमें से केवल एक सही है।
A : Horizontal range of a ground to ground projectile is same for angle of projection θ and (90° – θ).
A : धरातल से धरातल प्रक्षेप्य की क्षैतिज परास, प्रक्षेपण कोण θ तथा (90° – θ) के लिए समान है।
R : Horizontal range does not depend on angle of projection.
R : क्षैतिज परास, प्रक्षेपण कोण पर निर्भर नहीं करती है।
- (Both (A) and (R) are true and (R) is the correct explanation of (A)
(A) तथा (R) दोनों सही हैं तथा (R), (A) का सही स्पष्टीकरण है - Both (A) and (R) are true but (R) is not the correct explanation of (A)
(A) तथा (R) दोनों सही हैं लेकिन (R), (A) का सही स्पष्टीकरण नहीं है - (A) is true but (R) is false
(A) सही है लेकिन (R) गलत है - (A) is false but (R) is true
(A) गलत है लेकिन (R) सही है
- False
- True
- False
- True
A fighter plane flying horizontally at an altitude of with a speed of passes directly overhead an anti-aircraft gun. At what angle from the vertical should the gun be fired for the shell to hit the plane. The speed of the shell is . At what minimum altitude should the pilot fly the plane to avoid being hit ? [Take ]
- Kinetic energy of the ball
- Speed of the ball
- Horizontal component of velocity
- Vertical component of velocity
xy तल में गतिमान एक कण द्वारा अनुसरित प्रक्षेप-पथ को y = 4x – 3x2 द्वारा व्यक्त किया जाता है, जहाँ x, y मीटर में हैं। उन बिन्दुओं के मध्य दूरी ज्ञात कीजिए, जहाँ इसका y निर्देशांक शून्य है।
- 32m
- 43m
- 2 m
- 34m
- u2g
- u2g(sin α−cos α)
- u2g(2 cos α−sin α)
- u2g(2 sin α−cos α)
- 1
- √3
- √2
- √12
- vgcos(θ2)sin(θ)
- vgcos(θ2)sin(3θ2)
- vgcos(θ2)cosec(3θ2)
- vgcos(θ2)cosec(θ2)
- 20√3 m/s
- 20√3 m/s
- 10√3 m/s
- 10√3 m/s
Fill in the blanks using sign
- 196 m/s
- 138.5 m/s
- 240 m/s
- 144 m/s
- vgcos(θ2)sin(θ)
- vgcos(θ2)sin(3θ2)
- vgcos(θ2)cosec(3θ2)
- vgcos(θ2)cosec(θ2)
Fill in the blanks using sign
- True
- False
- 30 m/s
- 40 m/s
- 50 m/s
- 60 m/s
Reason : Acceleration is a vector quantity.
- both assertion and reason are true and the reason is the correct explanation of the assertion.
- both assertion and reason are true but reason is not the correct explanation of the assertion.
- assertion is true but reason is false.
- the assertion and reason both are false.
- assertion is false but reason is true.
Fill in the blanks using sign
Thief A is in an apartment 10m high and is throwing a bag of valuables horizontally at 5 m/s. Thief B is initially standing right below the point of release. Find the velocity with which he should run to catch the bag in time.
More than 5 m/s
Less than 5m/s
at 5 m/s
Data insufficient