Kirchoff's Voltage Law

Q.

State and explain Kirchhoffs Law.

Q.

Find the value of r if I-1A and potential difference across PQ is 1V

1. $5\Omega$

2. $10\Omega$

3. $20\Omega$

4. $25\Omega$

Q. An uncharged parallel-plate capacitor having a dielectric of dielectric constant $K$ is connected to a similar air cored parallel-plate capacitor charged to a potential $V_0$. The two share the charge and the common potential becomes $V$. The dielectric constant $K$ is

1. $\frac{V_0}{V}-1$
2. $\frac{V_0}{V}+1$
3. $\frac{V}{V_0}-1$
4. $\frac{V}{V_0}+1$

Q. Find the current $I_2$.

1. ${10}^{-4}A$
2. $2\times {10}^{-4}A$
3. $3\times {10}^{-4}A$
4. $5\times {10}^{-4}A$

Q. Abhishek is trying to solve this circuit question using Kirchhoff’s Voltage law.
And he arrives at this equation for the middle loop.
$(-I_2\times 6000)+(-I_3\times 3000)+(-I_4\times 4000)=0$
Is he correct?

1. Yes
2. No

Q. In the given circuit potential of junction $P$ is :

1. 4 V
2. 0 V
3. 3.2 V
4. 2.8 V

Q. In the given circuit all ammeters are ideal. Then choose correct statement.

1. Reading of $A_2$ = Reading of $A_5$
2. Reading of $A_2$ and reading of $A_4$ both are zero.
3. Reading of $A_1$ is 5 amp
4. Reading of $A_1=\frac{5}{2}$ times reading of $A_3$.

Q. In the given circuit with steady current the potential drop across the capacitor must be

1. V
2. $\frac{V}{2}$
3. $\frac{V}{3}$
4. $\frac{2V}{3}$

Q. Calculate currect ${}^{\prime }{I}^{\prime }$ in $10\Omega$ resistance.

1. $1\text{A}$
2. $2\text{A}$
3. $\frac{2}{5}\text{A}$
4. $\frac{1}{56}\text{A}$

Q. The potential difference $(V_A-V_B)$ between the points A and B in the given figure is

1. $+6V$
2. $+9V$
3. $-3V$
4. $+3V$

Q. The total current supplied to the circuit by the battery is

1. $4\text{A}$
2. $2\text{A}$
3. $1\text{A}$
4. $6\text{A}$

Q.

What is the current flowing through the $10\Omega$ resistor in the figure below?

1. 0.1 A
2. 0.2 A
3. 0.3 A
4. 0.4 A

Q. Current through wire $XY$ of circuit shown is

1. $1\text{A}$
2. $4\text{A}$
3. $2\text{A}$
4. $3\text{A}$

Q. Abhishek is trying to solve this circuit question using Kirchhoff’s Voltage law.
And he arrives at this equation for the middle loop.
$(-I_2\times 6000)+(-I_3\times 3000)+(-I_4\times 4000)=0$
Is he correct?

1. Yes
2. No

Q. The potential difference $(V_A-V_B)$ between the points A and B in the given figure is

1. $+6V$
2. $+9V$
3. $-3V$
4. $+3V$

Q. A circuit $\text{ABCD}$ is held perpendicular to the uniform magnetic field of $B=5\times {10}^{-2}\text{T}$ extending over the region $\text{PQRS}$ and directed into the plane of the paper. The circuit is moving out of the field at a uniform speed of $0.2{\text{ms}}^{-1}$ for $1.5\text{s}$. During this time, the current in the $5\Omega$ resistor is

1. $0.6\text{mA}$ from $\text{B}$ to $\text{C}.$
2. $0.9\text{mA}$ from $\text{C}$ to $\text{B}.$
3. $0.6\text{mA}$ from $\text{C}$ to $\text{B}.$
4. $0.9\text{mA}$ from $\text{B}$ to $\text{C}.$