Resultant Amplitude
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Q.
Two waves represented by y = a sin (wt − kx) and y = a cos (wt − kx) are superposed. The resultant wave will have an amplitude
a
√2a
2a
0
Q. Two waves, y1=2acosωt and y2=3acos(ωt+π2) meet at a point. The amplitude of the resultant wave is
- a
- 5a
- 3.6a
- 2.5a
Q.
Name the factors in Doppler effect on which the change in frequency depends.
Q. Two waves are passing simultaneously through a string.
The equation of the waves are given by,
y1=A1sink(x−vt)
and y2=A2sink(x−vt+x0)
Where the wave number k=6.28 cm−1 and x0=1.50 cm The amplitudes are A1=5.0 mm and A2=4.0 mm. Find the phase difference between the waves and the amplitude of the resulting wave.
The equation of the waves are given by,
y1=A1sink(x−vt)
and y2=A2sink(x−vt+x0)
Where the wave number k=6.28 cm−1 and x0=1.50 cm The amplitudes are A1=5.0 mm and A2=4.0 mm. Find the phase difference between the waves and the amplitude of the resulting wave.
- 2π and 1 mm
- 3π and 1 mm
- π and 2 mm
- π and 0.5 mm
Q. Two waves represented by equation y1=Asin(ωt−kx+ϕ1) and y2=Asin(ωt−kx+ϕ2) are superimposed such that the amplitude of resultant wave is A. Find the phase difference between them.
Given: (ϕ1>ϕ2)
Given: (ϕ1>ϕ2)
- 90∘
- 120∘
- 60∘
- 135∘
Q. Two identical travelling waves, moving in the same direction, are out of phase by π2 rad. If amplitude of each wave is A, then find the resultant amplitude of the wave after superimposition.
- 1.41A
- 2.16A
- 1.6A
- 6A
Q. Two sinusoidal waves each of amplitude 2A, travel in the same direction in a medium. If the phase difference between the two waves is 120∘, then find the resultant amplitude of the superimposed wave.
- 3√2A
- 2A
- √2A
- 3A
Q.
Two waves passing through a region are represented by
y = 1.0 cmsin [ (3.14 cm−1) x − (157 s−1)t]
and y = 1.5 cmsin [ (1.57 cm−1)x − (314 s−1) t]
Find the displacement of the particle at x = 4.5 cm at time t = 5.0 ms.
0.35 cm
(1√2)cm
(1.5√2)cm
- 0.35 cm
Q. A wave is represented by y1=10cos(5x+25t), where x and y are measured in centimetres and t in seconds. A second wave for which
y2=20cos(5x+25t+π/3) interferes with the first wave. Find the amplitude and phase of the resultant wave.
y2=20cos(5x+25t+π/3) interferes with the first wave. Find the amplitude and phase of the resultant wave.
- 26.46 cm, 0.71 rad
- 28.50 cm, 1 rad
- 30 cm, 0.71 rad
- 30.46 cm, 0.6 rad
Q. Two sources of sound A and B produce waves of 350 Hz. The particle at point P is vibrating under the influence of these two waves. The amplitudes of the two waves are 0.3 mm and 0.4 mm. If AP−BP=25 cm and velocity of sound is 350 m/s, the resultant amplitude of the particle at point P will be
- 0.7 mm
- 0.1 mm
- 0.2 mm
- 0.5 mm
Q. Two wave with same frequency and wave number are propagating in the same direction. The ratio of their amplitude is 5:1 . If interference occurs, the ratio of maximum and minimum intensity should be
- 9:4
- 3:2
- 1:4
- 4:1
Q. Two wave with same frequency and wave number are propagating in the same direction. The ratio of their amplitude is 5:1 . If interference occurs, the ratio of maximum and minimum intensity should be
- 9:4
- 3:2
- 1:4
- 4:1
Q. On the superposition of the two waves represented by equation,
y1=Asin(ωt−kx)
y2=Acos(ωt−kx+π6)
The resultant angular frequency of the oscillation will be
y1=Asin(ωt−kx)
y2=Acos(ωt−kx+π6)
The resultant angular frequency of the oscillation will be
- ω
- 2ω
- ω2
- 3ω
Q. Two waves y1=Asin(ωt−kx) and y2=Asin(ωt−kx+ϕ) are superimposed such that the resultant amplitude of oscillation is √2A, then the value of ϕ is
- π2
- π4
- π3
- π6
Q. Two waves of equal amplitude A, and equal frequency travel in the same direction in a medium. The amplitude of the resultant wave is
- \N
- A
- 2A
- between 0 and 2A
Q. Two waves are passing through a region in the same direction at the same time. If the equation of these waves are
y1=αsin2πλ(vt−x)
and y2=βsin2πλ[(vt−x)+ϕ],
then the amplitude of the resultant wave for ϕ=λ2 is
y1=αsin2πλ(vt−x)
and y2=βsin2πλ[(vt−x)+ϕ],
then the amplitude of the resultant wave for ϕ=λ2 is
- |α−β|
- α +β
- √α2+β2
- √α2+β2+2αβ cos x
Q. Two sinusoidal waves each of amplitude 2A, travel in the same direction in a medium. If the phase difference between the two waves is 120∘, then find the resultant amplitude of the superimposed wave.
- 3√2A
- 2A
- √2A
- 3A
Q. Three components of sinusoidal progressive waves travelling in the same direction along the same path having the same period, but with amplitudes A, A/2 and A/3. The phase of the vibration at any position x on their path at time t=0 are 0, −π/2 and π respectively. Find the amplitude and phase of the resultant wave
- 5A6, tan−1(3/4)
- 5A2, tan−1(4/3)
- 6A5, tan−1(2/3)
- 5A6, tan−1(4/3)
Q. Two monochromatic sinusoidal waves, each of intensity I, have a constant phase difference of ϕ. These waves when superimposed, form a resultant sinusoidal wave. Then, the intensity of the resultant wave is
- 4I
- 4Icosϕ
- 4Icos2ϕ
- 4Icos2(ϕ2)
Q. Two waves of equal amplitudes and wavelengths but differing in phase are superimposed. Amplitude of resultant wave is maximum when phase difference is
Q. Two waves of equal amplitude (A), frequency (f) and intensity (I) propagate along the same direction in a medium. The intensity of resultant wave will be:
- 0
- 2I
- 4I
- Between 0 and 4I
Q. Two waves y1=Asin(ωt−kx) and y2=Asin(ωt−kx+ϕ) are superimposed such that the resultant amplitude of oscillation is √2A, then the value of ϕ is
- π2
- π4
- π3
- π6
Q. On the superposition of the two waves represented by equation,
y1=Asin(ωt−kx)
y2=Acos(ωt−kx+π6)
The resultant angular frequency of the oscillation will be
y1=Asin(ωt−kx)
y2=Acos(ωt−kx+π6)
The resultant angular frequency of the oscillation will be
- ω
- 2ω
- ω2
- 3ω
Q. Two sinusoidal waves produced by two vibrating sources A and B of equal frequencies, are propagating to the point P along a straight line. The amplitude of both of the waves at P is ′a′ and the initial phase of A is ahead by π3 than that of B. The distance AP is greater than BP by 50 cm. If the wavelength is 1 m, then the resultant amplitude at the point P will be
- 2a
- a√3
- a√2
- a
Q. Two waves of equal amplitude (A), frequency (f) and intensity (I) propagate along the same direction in a medium. The intensity of resultant wave will be:
- 0
- 2I
- 4I
- Between 0 and 4I
Q. Two waves represented by equation y1=Asin(ωt−kx+ϕ1) and y2=Asin(ωt−kx+ϕ2) are superimposed such that the amplitude of resultant wave is A. Find the phase difference between them.
Given: (ϕ1>ϕ2)
Given: (ϕ1>ϕ2)
- 90∘
- 120∘
- 60∘
- 135∘
Q. On the superposition of the two waves represented by equation y1=Asin(ωt−kx) and y2=Asin(ωt−kx+π4), the resultant amplitude of oscillation will be:
- A√2
- A√2+√2
- A√2+√3
- A√1+√2
Q. On the superposition of the two waves represented by equation,
y1=Asin(ωt−kx)
y2=Acos(ωt−kx+π6)
The resultant angular frequency of the oscillation will be
y1=Asin(ωt−kx)
y2=Acos(ωt−kx+π6)
The resultant angular frequency of the oscillation will be
- ω
- 2ω
- ω2
- 3ω
Q. Two waves of equal frequencies have their amplitudes in the ratio of 3:5. They are superimposed on each other. The ratio of maximum and minimum intensities of the resultant wave is