You visited us 2 times! Enjoying our articles? Unlock Full Access!

Van't Hoff Factor

A 0.004 M sol...

Question

A $0.004 M$ solution of $N a_{2} S O_{4}$ is isotonic with a $0.010 M$ solution of glucose at same temperature. The apparent precentage degree of dissociation of $N a_{2} S O_{4}$ is:

25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

85

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $75$ %
Isotonic solution:
Two solutions having the same osmotic pressure across a semipermeable membrane is referred to as an isotonic solution

Osmotic pressure,
$π (N a_{2} S O_{4}) = i C R T = (0.004) i R T$
$π (g l u c o s e) = C R T = 0.010 R T ∵ i = 1 for non-electrolyte$
As solutions are isotonic,
$i (0.004) R T = 0.01 R T$
$i = 2.5$

$N a_{2} S O_{4} ⇌ 2 N a^{+} + S O_{4}^{2 -}$

1 mol 0 0

$1 - α$ $2 α$ $α$ ,

$n = 3$
we know,
$i = 1 + α (n - 1)$
$i = 1 + 2 α$

$α = \frac{i - 1}{2} = \frac{2.5 - 1}{2} = \frac{1.5}{2} = 0.75 = 75 %$

Suggest Corrections

Similar questions

Q. A

0.004

M solution of

N a_{2} S O_{4}

is isotonic with a

0.010

M solution of glucose at same temperature. The apparent degree of dissociation of

N a_{2} S O_{4}

is:

Q. A

0.004 M

solution of

{N a}_{2} S O_{4}

is isotonic with a

0.010 M

solution of glucose at the

25

. The apparent degree of dissociation of

{N a}_{2} S O_{4}

is:

Q. Aqueous solution of 0.004 M

N a_{2} S O_{4}

and 0.01 M glucose are isotonic. The degree of dissociation of

N a_{2} S O_{4}

is:

Q. 0.004 M

N a_{2} S O_{4}

is isotonic with 0.01 M Glucose. Degree of dissociation of

N a_{2} S O_{4}

is:

When $0.004 M N a_{2} S O_{4}$ is isotonic with 0.01M solution of glucose at same temperature.the apparent degree of dissociation of sodium sulphate is

Join BYJU'S Learning Program

Explore more

Van't Hoff Factor

Standard XII Chemistry

Join BYJU'S Learning Program

A 0.004 M solution of Na2SO4 is isotonic with a 0.010 M solution of glucose at same temperature. The apparent precentage degree of dissociation of Na2SO4 is:

A $0.004 M$ solution of $N a_{2} S O_{4}$ is isotonic with a $0.010 M$ solution of glucose at same temperature. The apparent precentage degree of dissociation of $N a_{2} S O_{4}$ is: