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Question

A 0.1 F capacitor is charged by a 10 V battery. After disconnecting the battery, this charged capacitor is connected with an uncharged capacitor. If the charge is equally shared between the two, then what will be the energy stored in the two capacitors? Compare this energy with the energy stored initially in the first capacitor.

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Solution

Dear student
Initial charge on the capacitor is q1=C×Vq1=0.1×10=1Cenergy stored in the capacitor is Ei=q122C=12×0.1=5JWhen connected with other capacitor charge is equally distributed it means capacitor of the other capacitor is also 0.1FFinal charge on both the capacitor is q2=12Cfinal energy of both the capacitors are equal Ef=q222×C=14×2×0.1=54=1.25JTotal final energy =2×1.25=2.5Jratio of final energy of single capacitor tothat of the initial energy of the capacitor isEfEi=1.255=0.25Regards

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