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Question

A 0.10 M solution of a weak acid, HX, is 0.059% ionized. Evaluate Ka for the acid.


A

3.8 x 10-9

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B

3.5 x 10-8

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C

7.0 x 10-6

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D

4.2 x 10-6

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Solution

The correct option is B

3.5 x 10-8


Since the acid is only 0.059% ionized, therefore the concentration of ions in solution = 0.1 x 0.059 / 100 = 0.000059

Ka = [H+] [X-] / [HX] = (0.000059)2 / 0.1 = 3.5 x 10-8


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