Question

A 0.5 m long solenoid has 500 turns and has a flux density of $2.25\times {10}^{-3}$ T at its centre. Find the current in the solenoid.

Answer 1

Formula,

$B=\frac{{\mu }_{0}NI}{l}$

$2.25\times {10}^{-3}=\frac{4\pi \times {10}^{-7}\times 500\times I}{0.5}$

$I=\frac{0.5\times 2.25\times {10}^{-3}}{4\pi \times {10}^{-7}\times 500}$

$\therefore I=1.79\approx 1.8A$