Question

A $1.0g$ sample of a pure organic compound containing chlorine is fused with $N{a}_2{O}_2$ to convert chlorine to $NaCl$. The sample is then dissolved in water, and the chloride precipitated with $AgN{O}_3$, giving $1.96g$ of $AgCl$. If the molecular weight of organic compound is $147$, how many chlorine atoms does each molecule contain?

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (B)

2

Moles of $AgCl=$moles of chloride$=\frac{1.96}{143.5}=0.0136$.
Moles of organic compound$=\frac{1}{147}=6.8\times {10}^{-3}$.
Chlorine atoms in each molecule of organic compound$=\frac{0.0136}{6.8\times {10}^{-3}}=2$.