Question

A $1.0$ g sample of a pure organic compound containing chlorine is fused with $N{a}_2{O}_2$ to convert chlorine to $NaCl$. The sample is then dissolved in water and the chloride precipitated out on adding $AgN{O}_3$ giving $1.96$ g of $AgCl$. If the molecular weight of organic compound is $147$ g/mol, how many chlorine atoms does each molecule contain?

Answer 1

Moles of $AgCl=$ Moles of chloride $=\frac{1.96}{143.5}=0.0136$
Moles of organic compound $=\frac{1}{147}=6.8\times {10}^{-3}$
Chlorine atoms in each molecule of organic compound $=\frac{0.0136}{6.8\times {10}^{-3}}=2$