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Question

A 1.5kg block is initially at rest on a horizontal frictionless surface when a horizontal force in the positive direction of the x-axis is applied to the block. The force is given by F=(4x2)^i N, where x is in meter and the initial position of the block is x=0.The maximum kinetic energy of the block between x=0 and x=2.0 m is

A
2.33J
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B
8.67J
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C
5.33J
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D
6.67J
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Solution

The correct option is C 5.33J
F=(4x2)^i
Maximum KE =20Fdx
=20(4x2)dx
=[4xx33]α0
=883
=5.33J.
Hence, the answer is 5.33J.

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