$A_{1}$ $g$ of an element gives $A_{2}$ of its oxide. The equivalent mass of the element is:

\frac{A_{2} - A_{1}}{A_{1}} \times 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{A_{2} - A_{1}}{A_{2}} \times 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{A_{1}}{A_{2} - A_{1}} \times 8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(A_{2} - A_{1}) \times 8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{A_{1}}{A_{2} - A_{1}} \times 8$
Given
$A_{1}$ g of element
$A_{2}$ g of oxide
Solution
Equivalent Mass of element is Mass of element comboned with 8 g of Oxygen
Mass of Oxygen Combined with element is $A_{2} - A_{1}$
Hence
$A_{2} - A_{1}$ g of oxygen combines with $A_{1}$ g of element
8g of oxygen will combine with $\frac{A_{1}}{A_{2} - A_{1}} * 8 g$
Hence correct option is C

Suggest Corrections

Similar questions

A . P .

a_{1}, a_{2}, a_{3}, . . . . . ., a_{n}, . . . . .

a_{1} + a_{3} + a_{5} = - 12

a_{1} a_{2} a_{3} = 8

a_{2} + a_{4} + a_{6}

a_{1}, a_{2}, a_{3}, . . . a_{n}

\frac{a_{1}}{a_{2} + a_{3} + . . . a_{n}}, \frac{a_{2}}{a_{1} + a_{3} + . . . a_{n}}, \frac{a_{3}}{a_{1} + a_{2} + a_{4} + . . . + a_{n}}, \frac{a_{n}}{a_{1} + a_{2} + . . . + a_{n}}

\frac{a_{1}}{a_{1}} + \frac{a_{2}}{a_{2}} + \frac{a_{3}}{a_{3}} + \dots \frac{a_{n}}{a_{n}} = \frac{1}{1} + \frac{1}{a_{1}} + \frac{a_{1}}{a_{2}} + \frac{a_{2}}{a_{3}} + \dots \frac{a_{n - 2}}{a_{n - 1}}

a_{1} = \frac{1}{2 \times 5}, a_{2} = \frac{1}{5 \times 8}, a_{3} = \frac{1}{8 \times 11}, . . .,

a_{1} + a_{2} + a_{3} + . . . + a_{100}

8

a_{1}, a_{2}, a_{3} . . . . . a_{8}

(a_{1} \times a_{2} \times a_{3} \times . . . . . . \times a_{8})^{8}

Join BYJU'S Learning Program