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Standard XII

Physics

Relative Position

A 1 kg body f...

Question

A $1 k g$ body falling vertically, hits the ground with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . What is the change in momentum of the body in $N s$ ?

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Solution

The correct option is C 35
Taking upward direction as positive,
$Δ p = m (v - u)$
= $1 \times [10 - (- 25)]$
= $35 N s$

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A 1 kg body falling vertically, hits the ground with a speed of 25 m/s and rebounds with a speed of 10 m/s. What is the change in momentum of the body in Ns?

The correct option is C 35Taking upward direction as positive, Δp=m(v−u) = 1×[10−(−25)] = 35 Ns

A $1 k g$ body falling vertically, hits the ground with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . What is the change in momentum of the body in $N s$ ?

The correct option is C 35
Taking upward direction as positive,
$Δ p = m (v - u)$
= $1 \times [10 - (- 25)]$
= $35 N s$