Question

# A body of mass 1 kg is projected from ground at an angle 30∘ with horizontal on a level ground at a speed 50 m/s. The magnitude of change in momentum of the body during its flight is (g=10 m/s2)

A
50 kg ms1
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B
100 kg ms1
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C
25 kg ms1
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D
Zero
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Solution

## The correct option is A. 50 kg ms−1.We know that in the horizontal plane, the initial velocity of projectile = final velocity of the projectile →pi=mucosθ^i+musinθ^j →pf=mucosθ^i−musinθ^j Δ→p=→pf−→pi=−2musinθ^j |Δ→p|=2musinθ =2×1×50×12=50 kg ms−1 Alternative: In the horizontal direction momentum does not change, Δ Px=0 In vertical direction ΔPy=(musinθ)−(−musinθ) (Take downward as positive) =2musinθ downward =2×1×50×12=50 kg ms−1

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