Projectile Time, Height and Range

Q. A stone is thrown at an angle $\theta$ to the horizontal reaches a maximum height H. Then the time of flight of stone will be

1. 
2. 
3. 
4. 

Q. A particle is projected with a velocity v such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where g is acceleration due to gravity)

1. 
2. 
3. 
4. 

Q. A ball is projected vertically upwards with a certain initial speed. Another ball of the same mass is projected at an angle of ${60}^{\circ }$ with the vertical with the same initial speed. At the highest point, the ratio of their potential energies will be

1. 3:2
2. 2:3
3. 2:1
4. 4:1

Q. For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 m$s^{-2}$)

1. 5 : 2
2. 5 : 4
3. 5 : 1
4. 10 : 1

Q. An object is projected with a velocity of 20 m/s making an angle of ${45}^{\circ }$ with horizontal. The equation for the trajectory is h = Ax – B$x^2$ where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 m$s^{-2}$)

1. 1 : 5
2. 1 : 40
3. 40 : 1
4. 5 : 1

Q. A ball is rolled off the edge of a horizontal table at a speed of 4 m/s. It hits the ground after 0.4 second. Which statement given below is true(Take $g=10m/s^2$)

1. It hits the ground at an angle of 60^o to the horizontal
2. The speed with which it hits the ground is 4.0 m/second
3. It hits the ground at a horizontal distance 1.6 m from the edge of the table
4. Height of the table is 1.8 m

Q. A stone projected with a speed u at an angle θ with the horizontal reaches maximum height $H_1$. When it is projected with speed u at an angle $90-\theta$ with the horizontal, it reaches maximum height $H_2$. The relation between the horizontal range R of the projectile, $H_1$ and $H_2$ is

1. 
2. R = 4(H₁ - H₂)
3. 
4. 

Q. A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle with the horizontal at which it strikes the ground will be (g=10 m/$s^2$)

1. 
2. 
3. 
4. 

Q. For a given velocity, a projectile has the same range R for two angles of projection. If t₁ and t₂ are the times of flight in the two cases then

1. 
2. 
3. 
4. 

Q.

A particle is projected from the ground at t = 0 so that on its way it just clears two vertical walls of equal height on the ground. If the particle passes just grazing top of the wall at time $t_{1}and{t}_2$ then calculate

the height of the wall

1. h = g

2. h + g

3. h = g

4. h + g