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Question

# A body of mass 1 kg is projected at an angle 30∘ with horizontal on a level ground at a speed 50 m/s. The magnitude of change in momentum of the body during its flight is (g=10 m/s2)

A
50 kg ms1
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B
100 kg ms1
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C
25 kg ms1
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D
Zero
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Solution

## The correct option is A 50 kg ms−1 We know that in a horizontal plane, Initial velocity of projectile = Final velocity of projectile →pi=mucosθ^i+musinθ^j→pf=mucosθ^i−musinθ^j|−→Δp|=|→pf−→pi|=2musinθ =2×1×50×12=50 kg ms−1 Alternate Solution: In the horizontal direction, momentum p doesn’t change. Δpx=0 In vertical direction, Δpy=musinθ−(−musinθ)=2musinθ =2×1×50×12=50 kg ms−1

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