A $1 k g$ body falls vertically with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . What is the impulse acting on the body.

35 N - s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 N - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 N - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 N - s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $35 N - s$
Taking upward direction as positive, $I = Δ p = m (\to v - \to u)$
$= 1 [10 - (- 25)]$ = $35 N - s$

Suggest Corrections

Similar questions

A $1 k g$ body falling vertically, hits the ground with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . What is the change in momentum of the body in $N s$ ?

Q. A

1 k g

body falls vertically with a speed of

25 m / s

and rebounds with a speed of

10 m / s

. If the time for which the ball is in contact with the ground is

1 m s

, what is the contact force on the body by the ground?

Q. A

1

kg ball drops vertically onto the floor with a speed of

25

m/s and rebounds with a speed of

10

m/s What is the impulse acting on the ball?

Momentum of a body of mass 0.5 kg moving with a speed of 10 m/s is

Q. A body of mass

5 kg

is acted upon by a variable force which varies with the displacement of the body as shown in figure. What is the speed of the body when it has covered

25 m

? (Assume that the body starts from rest.)

Join BYJU'S Learning Program

A 1 kg body falls vertically with a speed of 25 m/s and rebounds with a speed of 10 m/s. What is the impulse acting on the body.

The correct option is A 35 N−sTaking upward direction as positive, I=Δp=m(→v−→u) =1[10−(−25)] = 35 N−s

A $1 k g$ body falls vertically with a speed of $25 m / s$ and rebounds with a speed of $10 m / s$ . What is the impulse acting on the body.

The correct option is A $35 N - s$
Taking upward direction as positive, $I = Δ p = m (\to v - \to u)$
$= 1 [10 - (- 25)]$ = $35 N - s$