Question

A $1kW$ carrier is modulated to a depth of $80\%$. The total power in the modulated wave is

• A. $1.32$
• B. $1.56$
• C. $1.84$
• D. $1.96$

Answer 1

Answer: (A)

$1.32$

We have the power consumed by the side frequencies as $P_{SF}=\frac{m_a^2}{2}{P}_C$
$P_{SF}=\frac{{0.8}^2}{2}\left(1\right)=0.32kW$
Thus, total power in the modulated wave is $1+0.32=1.32kW$