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Question

# A 10.0 g sample of a mixture of calcium chloride and sodium chloride is treated with Na2CO3 to precipiate the calcium as calcium carbonate. This CaCO3 is heated to convert all the calcium to CaO and the final mass of CaO is 1.62 g. The % by mass of CaCl2 in the original mixture is

A
15.2%
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B
32.1%
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C
21.8%
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D
11.7%
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Solution

## The correct option is B 32.1%Let the mass of CaCl2 in sample = x g CaCl2+Na2CO3→CaCO3+2NaCl 111 g 100 g ∴111 g CaCl2 produces 100 g CaCO3 Hence x g CaCl2 produces 100x111 g CaCO3 CaCO3 Δ→ CaO + CO2 100 g 56 g ∴100 g CaCO3 produces 56 g CaO (100x111)g CaCO3 produces 56100×100111x g CaO=56x111g CaO Since mass of CaO finally produced =1.62 g⇒56111x=1.62 g ⇒x=3.21 g % of CaCl2 in sample =3.2110×100=32.1%

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