A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0-0125 m3 at 6 bar and 27- C-The mass of helium in the mixture is g-nearest integerGiven - R - 8-3 J K-1 mol-1Atomic masses of H and He are 1 u and 4 u- respectively

Number of moles of mixture of H_2 and He =PVRT =6×10^5×0.01258.3×300=3 Let the mass of He in 10 g mixture be x g ∴ x4+10 x2=3 On solving x = 8 g ∴ nbsp;Ma ...

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Standard X

Chemistry

Mole Concept and Avogadro's Number

A 10 g mixtur...

Question

A $10 g$ mixture of hydrogen and helium is contained in a vessel of capacity $0.0125 m^{3}$ at 6 bar and $27^{\circ} C$ .
The mass of helium in the mixture is g.

(nearest integer)
Given : $R = 8.3 J K^{- 1} m o l^{- 1}$

(Atomic masses of $H$ and $H e$ are $1 u$ and $4 u$ , respectively)

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Solution

Number of moles of mixture of $H_{2}$ and $H e$
$= \frac{P V}{R T}$
$= \frac{6 \times 10^{5} \times 0.0125}{8.3 \times 300} = 3$
Let the mass of $H e$ in $10 g$ mixture be $x g$
$∴ \frac{x}{4} + \frac{10 - x}{2} = 3$
On solving $x = 8 g$
$∴$ Mass of $H e$ in the mixture $= 8 g$

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A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0.0125 m3 at 6 bar and 27∘ C. The mass of helium in the mixture is g. (nearest integer) Given : R=8.3 JK−1 mol−1 (Atomic masses of H and He are 1 u and 4 u, respectively)

Number of moles of mixture of H2 and He =PVRT =6×105×0.01258.3×300=3 Let the mass of He in 10 g mixture be x g ∴ x4+10−x2=3 On solving x=8 g ∴ Mass of He in the mixture =8 g

A $10 g$ mixture of hydrogen and helium is contained in a vessel of capacity $0.0125 m^{3}$ at 6 bar and $27^{\circ} C$ .
The mass of helium in the mixture is g.

(nearest integer)
Given : $R = 8.3 J K^{- 1} m o l^{- 1}$

(Atomic masses of $H$ and $H e$ are $1 u$ and $4 u$ , respectively)

Number of moles of mixture of $H_{2}$ and $H e$
$= \frac{P V}{R T}$
$= \frac{6 \times 10^{5} \times 0.0125}{8.3 \times 300} = 3$
Let the mass of $H e$ in $10 g$ mixture be $x g$
$∴ \frac{x}{4} + \frac{10 - x}{2} = 3$
On solving $x = 8 g$
$∴$ Mass of $H e$ in the mixture $= 8 g$