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Impulsive Forces in Collision

A 10 kg block...

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A 10 kg block of steel is at rest on a horizontal table . the coefficient of static friction between block and table is 0.5. what is the magnitugde of a force acting upward 37^° from horizontal that will just start the block movin

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Q. A block of mass

1 kg

is at rest on a horizontal table. The coefficient of static friction between the block and the table is

0.50

g = 10 {ms}^{- 2}

, then the magnitude of a force (in

N

) acting upwards at an angle of

60^{\circ}

from the horizontal that will just start the block moving is

Q. A block of mass

1 kg

is at rest on a horizontal table. The coefficient of static friction between the block and the table is

0.50

g = 10 {ms}^{- 2}

, then the magnitude of a force (in

N

) acting upwards at an angle of

60^{\circ}

from the horizontal that will just start the block moving is

Q. A block of mass

1 k g

is at rest on a horizontal table. The coefficient of static friction between the block and the table is

0.50

g = 10 m s^{- 2}

, then the magnitude of a force acting upwards at an angle of

60^{o}

from the horizontal that will just start the block moving is:

Q. A block weighing

10 k g

is at rest on a horizontal table. The coefficient of static friction between the block and the table is

0.5

. If a force acts down at

60^{0}

from the horizontal, how large can it be without causing the block to move? (

g = 10 m s^{- 2}

)

Q. A block of mass

10 K g

is placed on a rough horizontal table whose coefficient of static friction

μ_{s}

0.5

F

acting on the block at angle of

37^{\circ}

is gradually increased from zero. Determine whether the block will first slide or lift up?

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