Question

A 10 kg mass moves along x-axis. Its acceleration as function of its position is shown in the figure. What is the total work done on the mass moves from $x=0$ to $x=8cm$?

Answer 1

We know that $dW=F.dx=ma.dx$

$⟹W=m\int a.dx=m\times$area under a-x graph

$⟹W=10kg\times \frac{1}{2}\times 20\times 8c{m}^2$

$⟹W=800\times {10}^{-4}J$

$⟹W=0.08J$