A $10$ kg satellite completes one revolution around the earth at a height of $100$ km in $108$ minutes. The work done by the gravitational force of earth will be?

108 \times 100 \times 10

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\frac{108 \times 10}{100}

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\frac{100 \times 10}{108}

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Solution

The correct option is C $0$ J
Listing out the Formula
Work Done = Force x Displacement
Force = Mass x Acceleration
Considering the displacement of this Sattelite
One complete circle = Displacement = 0
∴ Work Done by Gravity is Zero

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A 10 kg satellite completes one revolution around the earth at a height of 100 km in 108 minutes. The work done by the gravitational force of earth will be?

The correct option is C 0JListing out the FormulaWork Done = Force x DisplacementForce = Mass x AccelerationConsidering the displacement of this SatteliteOne complete circle = Displacement = 0∴ Work Done by Gravity is Zero

A $10$ kg satellite completes one revolution around the earth at a height of $100$ km in $108$ minutes. The work done by the gravitational force of earth will be?

The correct option is C $0$ J
Listing out the Formula
Work Done = Force x Displacement
Force = Mass x Acceleration
Considering the displacement of this Sattelite
One complete circle = Displacement = 0
∴ Work Done by Gravity is Zero