A $100 g$ mass attached to the end of a string is rotated in a vertical circle of radius $40 c m$ .What is the total energy of the mass at the highest point? (in $J$ )

0.45

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0.39

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0.98

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0.63

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Solution

The correct option is C $0.98$
$m = 100 g = 0.100 k g, r = 40 c m = 0.40 m$
the energy of mass at highest point is given by
$E = \frac{5}{2} m g r = \frac{5}{2} * 0.100 * 0.40 * 9.8 = 0.98 J$

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A 100g mass attached to the end of a string is rotated in a vertical circle of radius 40cm.What is the total energy of the mass at the highest point? (in J)

The correct option is C 0.98m=100g=0.100kg,r=40cm=0.40mthe energy of mass at highest point is given byE=52mgr=52∗0.100∗0.40∗9.8=0.98J

A $100 g$ mass attached to the end of a string is rotated in a vertical circle of radius $40 c m$ .What is the total energy of the mass at the highest point? (in $J$ )

The correct option is C $0.98$
$m = 100 g = 0.100 k g, r = 40 c m = 0.40 m$
the energy of mass at highest point is given by
$E = \frac{5}{2} m g r = \frac{5}{2} * 0.100 * 0.40 * 9.8 = 0.98 J$