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Question

A 100 -milliliter solution of AgNO3 and excess NaCl were treated and the silver was precipitate as AgCl . If 5.7 g AgCl was obtained, what was the concentration of Ag+ in the original solution?

A
0.03 M
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B
0.05 M
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C
0.12 M
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D
0.30 M
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E
0.40 M
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Solution

The correct option is E 0.40 M
The molar mass of AgCl is 108+35.5=143.5 g/mol.
Number of moles is the ratio of mass to molar mass.
Number of moles of AgCl =5.7g143.5g/mol=0.0397 moles.
0.0397 moles of AgCl are obtained from 0.0397 moles of Ag+.
Molarity of Ag+=0.0397mol0.100L=0.4M
Hence, the option (E) is the correct answer.

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