A 100 -milliliter solution of AgNO3 and excess NaCl were treated and the silver was precipitate as AgCl . If 5.7 g AgCl was obtained, what was the concentration of Ag+ in the original solution?
A
0.03 M
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B
0.05 M
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C
0.12 M
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D
0.30 M
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E
0.40 M
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Solution
The correct option is E0.40 M The molar mass of AgCl is 108+35.5=143.5 g/mol. Number of moles is the ratio of mass to molar mass. Number of moles of AgCl=5.7g143.5g/mol=0.0397 moles. 0.0397 moles of AgCl are obtained from 0.0397 moles of Ag+. Molarity of Ag+=0.0397mol0.100L=0.4M Hence, the option (E) is the correct answer.