A 100N force acts horizontally on a block of mass 10kg placed on a horizontal rough table of coefficient of friction μ=0.5. If g at the place is 10ms−2 the acceleration of the block is:
A
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10ms−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5ms−2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5.2ms−2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C5ms−2 limiting friction=μmg=0.5×10g=50N