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Question

A 100% pure sample of a divalent metal carbonate weighing 2 g on complete thermal decomposition releases 448 cc of carbon dioxide at STP. The equivalent mass of the metal is:

A
40
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B
20
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C
28
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D
12
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E
56
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Solution

The correct option is B 20

Let the metal is M, so the formula of its carbonate is MCO3.

Molar mass of MCO3=x+12+3×16

=(x+60)g/mol

(Let atomic mass of M is x.)

448cc(448mL)CO2 is produced from carbonate =2g.

22400ccCO2 will be obtained from carbonate =2×22400448=100g

100=x+60

x=10060=40g/mol

Eq. wt. of metal =402=20gequiv1


737745_676844_ans_9c1a79707f17433eb9bcd71ee4209292.jpg

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