A 100% pure sample of a divalent metal carbonate weighing 2 g on complete thermal decomposition releases 448 cc of carbon dioxide at STP. The equivalent mass of the metal is:
Let the metal is M, so the formula of its carbonate is MCO3.
Molar mass of MCO3=x+12+3×16
=(x+60)g/mol
(Let atomic mass of M is x.)
∵448cc(448mL)CO2 is produced from carbonate =2g.
∴22400ccCO2 will be obtained from carbonate =2×22400448=100g
∴100=x+60
x=100−60=40g/mol
Eq. wt. of metal =402=20gequiv−1