wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 100 W bulb B1, and two 60 W bulbs B2 and B3, are connected to a 250 V source as shown in the figure. Now W1,W2 and W3 are the output powers of the bulbs B1,B2 and B3 respectively. Then


A

W1>W2=W3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

W1>W2>W3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

W1<W2=W3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

W1<W2<W3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

W1<W2<W3


Let the resistance of 100 W bulb is R1 and that of 60 W bulb is R2. From the given data we can conclude that R1<R2.

Now if we observe the current in the branches, we can say that the current in B3 is more than that of B1 and B2.

Both these observations says that the power output can be arranged as :

W1<W2<W3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon