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Question

A 100 watts bulb has an efficiency of 80%. The wavelength of the radiation emitted is 595.80 nm. Which of the following statement(s) is/are true?

A
Number of photons emitted per second is 24×1019
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B
80 J of energy is emitted as light.
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C
If the efficiency is 50%, then the number of photons emitted is 15×1019
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D
All of the above
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Solution

The correct option is D All of the above
Efficiency of the bulb is 80%. Only 80% energy is emitted as light.

In one second, energy emitted as light
=100×80100=80 J

Energy of one photon =6.62×1034×3×108595.80×109
=13×1018

Number of photons =8013×1018=24×1019

If the efficiency of the bulb = 50%
The energy of light emitted per second =100×50100=50 J

Number of photons =5013×1018=15×1019

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